We read your photo as:

Given the sum of the first n terms of a sequence is Sn = 3n2 + n, find the formula for the n-th term, Tn.

Mathematics

ScanSolve AI Answer

Answer

Tn=6n−2T_n = 6n - 2

Step-by-step solution

4 steps
  1. Write the given formula for the sum of the first nn terms, SnS_n.

    Sn=3n2+nS_n = 3n^2 + n
  2. Find the formula for the sum of the first (n−1)(n-1) terms, Sn−1S_{n-1}, by replacing nn with (n−1)(n-1) in the SnS_n formula.

    Sn−1=3(n−1)2+(n−1)S_{n-1} = 3(n-1)^2 + (n-1)

    Expand the term (n−1)2(n-1)^2:

    Sn−1=3(n2−2n+1)+(n−1)S_{n-1} = 3(n^2 - 2n + 1) + (n-1)

    Distribute the 3:

    Sn−1=3n2−6n+3+n−1S_{n-1} = 3n^2 - 6n + 3 + n - 1

    Combine like terms:

    Sn−1=3n2−5n+2S_{n-1} = 3n^2 - 5n + 2
  3. Use the relationship Tn=Sn−Sn−1T_n = S_n - S_{n-1} to find the nn-th term, TnT_n.

    Tn=(3n2+n)−(3n2−5n+2)T_n = (3n^2 + n) - (3n^2 - 5n + 2)
  4. Simplify the expression.

    Tn=3n2+n−3n2+5n−2T_n = 3n^2 + n - 3n^2 + 5n - 2

    Combine the n2n^2 terms: 3n2−3n2=03n^2 - 3n^2 = 0.
    Combine the nn terms: n+5n=6nn + 5n = 6n.
    The constant term is −2-2.

    Tn=6n−2T_n = 6n - 2

    The nn-th term is:

Was this helpful?

Try one yourself

A new problem that tests the same skill.

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question
Handwritten step-by-step solution preview

Handwritten Step-by-Step Solution

Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.

Try on WhatsApp