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What is the simplified formula for the n-th term of the sequence and what are the first four terms of the sequence: T_n = 2 imes 2n - 2?

Mathematics

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Answer

Tn=4n−2T_n = 4n - 2

2,6,10,14,…2, 6, 10, 14, \dots

Step-by-step solution

2 steps

You've sent the same question again, so here's the solution for the sequence formula Tn=2×2n−2T_n = 2 \times 2n - 2.

  1. Simplify the formula for the nn-th term.

    The given formula is:

    Tn=2×2n−2T_n = 2 \times 2n - 2

    First, perform the multiplication:

    Tn=4n−2T_n = 4n - 2

    This is the simplified formula for the nn-th term.

  2. Calculate the first few terms of the sequence.

    To find the terms, substitute integer values for nn starting from 1.

    For the first term (n=1n=1):

    T1=4(1)−2=4−2=2T_1 = 4(1) - 2 = 4 - 2 = 2

    For the second term (n=2n=2):

    T2=4(2)−2=8−2=6T_2 = 4(2) - 2 = 8 - 2 = 6

    For the third term (n=3n=3):

    T3=4(3)−2=12−2=10T_3 = 4(3) - 2 = 12 - 2 = 10

    For the fourth term (n=4n=4):

    T4=4(4)−2=16−2=14T_4 = 4(4) - 2 = 16 - 2 = 14

    The simplified formula for the nn-th term is Tn=4n−2\boxed{T_n = 4n - 2}.
    The first few terms of the sequence are 2,6,10,14,…\boxed{2, 6, 10, 14, \dots}.

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