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Given two algebraic expressions E1 = 2x2 − 4x + 6 and E2 = 8x2 + 4x − 2, find their sum, difference, value at x=1, and value of sum at x=-2.

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Answers

5 parts
a

10x2+410x^2 + 4

b

−6x2−8x+8-6x^2 - 8x + 8

c
4
10
d
44
e
-22

Step-by-step solution

11 steps

Here are the solutions for each part of the problem.

Let the two algebraic expressions be:
E1=2x2−4x+6E_1 = 2x^2 - 4x + 6
E2=8x2+4x−2E_2 = 8x^2 + 4x - 2

Part a· 2 steps

Find the sum of the two expressions.

  1. Add the two expressions.

    E1+E2=(2x2−4x+6)+(8x2+4x−2)E_1 + E_2 = (2x^2 - 4x + 6) + (8x^2 + 4x - 2)
  2. Combine like terms.

    E1+E2=(2x2+8x2)+(−4x+4x)+(6−2)E_1 + E_2 = (2x^2 + 8x^2) + (-4x + 4x) + (6 - 2) E1+E2=10x2+0x+4E_1 + E_2 = 10x^2 + 0x + 4 E1+E2=10x2+4E_1 + E_2 = \boxed{10x^2 + 4}

Part b

−6x2−8x+8-6x^2 - 8x + 8

Find the difference between the two expressions.

  1. Subtract the second expression from the first.

    E1−E2=(2x2−4x+6)−(8x2+4x−2)E_1 - E_2 = (2x^2 - 4x + 6) - (8x^2 + 4x - 2)
  2. Distribute the negative sign.

    E1−E2=2x2−4x+6−8x2−4x+2E_1 - E_2 = 2x^2 - 4x + 6 - 8x^2 - 4x + 2
  3. Combine like terms.

    E1−E2=(2x2−8x2)+(−4x−4x)+(6+2)E_1 - E_2 = (2x^2 - 8x^2) + (-4x - 4x) + (6 + 2) E1−E2=−6x2−8x+8E_1 - E_2 = -6x^2 - 8x + 8 E1−E2=−6x2−8x+8E_1 - E_2 = \boxed{-6x^2 - 8x + 8}

Part c4

If x=1x = 1, find the number value of each expression.

  1. Substitute x=1x=1 into E1E_1.

    E1=2(1)2−4(1)+6E_1 = 2(1)^2 - 4(1) + 6 E1=2(1)−4+6E_1 = 2(1) - 4 + 6 E1=2−4+6E_1 = 2 - 4 + 6 E1=−2+6E_1 = -2 + 6 E1=4E_1 = \boxed{4}
  2. Substitute x=1x=1 into E2E_2.

    E2=8(1)2+4(1)−2E_2 = 8(1)^2 + 4(1) - 2 E2=8(1)+4−2E_2 = 8(1) + 4 - 2 E2=8+4−2E_2 = 8 + 4 - 2 E2=12−2E_2 = 12 - 2 E2=10E_2 = \boxed{10}

Part d44

If x=−2x = -2, what is the number value of the sum of the expressions?

  1. Use the sum expression from part a), S(x)=10x2+4S(x) = 10x^2 + 4.

  2. Substitute x=−2x=-2 into the sum expression.

    S(−2)=10(−2)2+4S(-2) = 10(-2)^2 + 4 S(−2)=10(4)+4S(-2) = 10(4) + 4 S(−2)=40+4S(-2) = 40 + 4 S(−2)=44S(-2) = \boxed{44}

Part e-22

If x=−3x = -3, what is the number value of the difference of the expressions?

  1. Use the difference expression from part b), D(x)=−6x2−8x+8D(x) = -6x^2 - 8x + 8.

  2. Substitute x=−3x=-3 into the difference expression.

    D(−3)=−6(−3)2−8(−3)+8D(-3) = -6(-3)^2 - 8(-3) + 8 D(−3)=−6(9)−(−24)+8D(-3) = -6(9) - (-24) + 8 D(−3)=−54+24+8D(-3) = -54 + 24 + 8 D(−3)=−30+8D(-3) = -30 + 8 D(−3)=−22D(-3) = \boxed{-22}
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