Given vectors a = 2i + 5j - k and b = 3i - 2j + 4k, find a x b, b x a, and (a + b) x (a - b).
|Mathematics
Given vectors a = 2i + 5j - k and b = 3i - 2j + 4k, find a x b, b x a, and (a + b) x (a - b).
ScanSolve AI Answer
Answer
18i - 11j - 19k
Given the vectors:
a=2i+5j−kb=3i−2j+4k
We need to find (i) a×b, (ii) b×a, and (iii) (a+b)×(a−b).
i) Find a×b.
Step 1: Set up the determinant for the cross product.
The cross product a×b is calculated as:
a×b=i23j5−2k−14
Step 2: Calculate the components of the cross product.
a×b=((5)(4)−(−1)(−2))i−((2)(4)−(−1)(3))j+((2)(−2)−(5)(3))ka×b=(20−2)i−(8−(−3))j+(−4−15)ka×b=18i−(8+3)j−19ka×b=18i−11j−19k
The result for (i) is 18i−11j−19k.
ii) Find b×a.
Step 1: Use the property of cross products that b×a=−(a×b).
Using the result from part (i):
b×a=−(18i−11j−19k)b×a=−18i+11j+19k
The result for (ii) is −18i+11j+19k.
Step 3: Set up the determinant for the cross product of (a+b) and (a−b).
(a+b)×(a−b)=i5−1j37k3−5
Step 4: Calculate the components of the cross product.
(a+b)×(a−b)=((3)(−5)−(3)(7))i−((5)(−5)−(3)(−1))j+((5)(7)−(3)(−1))k(a+b)×(a−b)=(−15−21)i−(−25−(−3))j+(35−(−3))k(a+b)×(a−b)=−36i−(−25+3)j+(35+3)k(a+b)×(a−b)=−36i−(−22)j+38k(a+b)×(a−b)=−36i+22j+38k
The result for (iii) is −36i+22j+38k.
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This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.
ScanSolve AI Answer
Given the vectors: a = 2i + 5j - k b = 3i - 2j + 4k We need to find (i) a × b, (ii) b × a, and (iii) (a + b) × (a - b). i) Find a × b. Step 1: Set up the determinant for the cross product. The cross product a × b is calculated as: a × b = i & j & k \\ 2 & 5 & -1 \\ 3 & -2 & 4 Step 2: Calculate the components of the cross product. a × b = ( (5)(4) - (-1)(-2) )i - ( (2)(4) - (-1)(3) )j + ( (2)(-2) - (5)(3) )k a × b = (20 - 2)i - (8 - (-3))j + (-4 - 15)k a × b = 18i - (8 + 3)j - 19k a × b = 18i - 11j - 19k The result for (i) is 18i - 11j - 19k. ii) Find b × a. Step 1: Use the property of cross products that b × a = -(a × b). Using the result from part (i): b × a = -(18i - 11j - 19k) b × a = -18i + 11j + 19k The result for (ii) is -18i + 11j + 19k. iii) Find (a + b) × (a - b). Step 1: Calculate a + b. a + b = (2i + 5j - k) + (3i - 2j + 4k) a + b = (2+3)i + (5-2)j + (-1+4)k a + b = 5i + 3j + 3k Step 2: Calculate a - b. a - b = (2i + 5j - k) - (3i - 2j + 4k) a - b = (2-3)i + (5-(-2))j + (-1-4)k a - b = -1i + 7j - 5k Step 3: Set up the determinant for the cross product of (a + b) and (a - b). (a + b) × (a - b) = i & j & k \\ 5 & 3 & 3 \\ -1 & 7 & -5 Step 4: Calculate the components of the cross product. (a + b) × (a - b) = ( (3)(-5) - (3)(7) )i - ( (5)(-5) - (3)(-1) )j + ( (5)(7) - (3)(-1) )k (a + b) × (a - b) = (-15 - 21)i - (-25 - (-3))j + (35 - (-3))k (a + b) × (a - b) = -36i - (-25 + 3)j + (35 + 3)k (a + b) × (a - b) = -36i - (-22)j + 38k (a + b) × (a - b) = -36i + 22j + 38k The result for (iii) is -36i + 22j + 38k. 3 done, 2 left today. You're making progress.