Given x = (12)/(5). In a right-angled triangle, x = OppositeAdjacent.

Given $\tan x = \frac{12}{5}$. In a right-angled triangle, $\tan x = \frac{\text{Opposite}}{\text{Adjacent}}$.
Let the opposite side be $12k$ and the adjacent side be $5k$ for some constant $k$.
Using the Pythagorean theorem, the hypotenuse $H$ is:

$$H = \sqrt{(12k)^2 + (5k)^2} = \sqrt{144k^2 + 25k^2} = \sqrt{169k^2} = 13k$$

Now, we can find $\sin x$ and $\cos x$:

$$\sin x = \frac{\text{Opposite}}{\text{Hypotenuse}} = \frac{12k}{13k} = \frac{12}{13}$$ $$\cos x = \frac{\text{Adjacent}}{\text{Hypotenuse}} = \frac{5k}{13k} = \frac{5}{13}$$

The expression is $\frac{\sin x + 2 \cos x}{1 - \sin x}$.
Substitute $\sin x = \frac{12}{13}$ and $\cos x = \frac{5}{13}$:

$$\frac{\frac{12}{13} + 2 \left(\frac{5}{13}\right)}{1 - \frac{12}{13}}$$

$$\frac{\frac{22}{13}}{\frac{1}{13}} = \frac{22}{13} \times \frac{13}{1} = 22$$

The value of the expression is 22.