Given (x+2)(y+3)=1, write y in the form y = racax+p + q.

Here's the continuation of the solution for Question 1:

1.2 Write $g$ in the form $y = \frac{a}{x+p} + q$.

Step 1: Start with the given equation for $g$ and the value of $t$ found in 1.1.2.1.
We have $(x+2)(y+3) = t$. From 1.1.2.1, $t=1$.

$$(x+2)(y+3) = 1$$

Step 2: Isolate $y+3$.

$$y+3 = \frac{1}{x+2}$$

Step 3: Isolate $y$.

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