Given z1 = 3+2i and z2 = -1-5i, find (z1)/(z2) and choose the correct option.

Given $z_1 = 3+2i$ and $z_2 = -1-5i$, we have:

$$\frac{z_1}{z_2} = \frac{3+2i}{-1-5i}$$

The conjugate of $-1-5i$ is $-1+5i$.

$$\frac{3+2i}{-1-5i} \times \frac{-1+5i}{-1+5i}$$

$$(3+2i)(-1+5i) = 3(-1) + 3(5i) + 2i(-1) + 2i(5i)$$ $$= -3 + 15i - 2i + 10i^2$$

Since $i^2 = -1$:

$$= -3 + 13i + 10(-1)$$ $$= -3 + 13i - 10$$ $$= -13 + 13i$$

The denominator is in the form $(a-bi)(a+bi) = a^2 + b^2$. Here, $a=-1$ and $b=5$.

$$(-1-5i)(-1+5i) = (-1)^2 + (5)^2$$ $$= 1 + 25$$ $$= 26$$

$$\frac{z_1}{z_2} = \frac{-13}{26} + \frac{13}{26}i$$ $$\frac{z_1}{z_2} = -\frac{1}{2} + \frac{1}{2}i$$

The calculated answer is $-\frac{1}{2} + \frac{1}{2}i$.
Based on the image, option A appears to be $-\frac{1}{2} + \frac{1}{2}i$. Due to the blurriness of the image, this is the closest match.

The final answer is $\text{A. } -\frac{1}{2} + \frac{1}{2}i$.