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Find the gradient of the graph of y = 1/3(29x + 10) + 5x in the x-y plane.

Mathematics

ScanSolve AI Answer

Answer

D
Graph of y = 1/3(29x + 10) + 5x

Use the left and right arrow keys to trace the curve, up and down to jump between key points, and plus and minus to zoom.

Key points of y = 1/3(29x + 10) + 5x
Pointxy
x-intercept−0.230
y-intercept03.33

Step-by-step solution

4 steps
  1. Draw a diagram to represent the situation.

    Let the height of the pole be hh.
    Let the foot of the pole be point BB and the top of the pole be point AA.
    Let point MM be on the horizontal ground, 10 m10 \text{ m} from the foot of the pole.
    This forms a right-angled triangle ABMABM, where the angle at BB is 90∘90^\circ.
    The angle of elevation from MM to the top of the pole (AA) is ∠AMB=55∘\angle AMB = 55^\circ.
    The side ABAB is opposite to the angle 55∘55^\circ.
    The side BMBM is adjacent to the angle 55∘55^\circ.

  2. Choose the appropriate trigonometric ratio.

    We know the adjacent side (BM=10 mBM = 10 \text{ m}) and we want to find the opposite side (AB=hAB = h). The tangent function relates the opposite and adjacent sides:

    tan⁡(θ)=OppositeAdjacent\tan(\theta) = \frac{\text{Opposite}}{\text{Adjacent}}
  3. Set up the equation and solve for hh.

    Substitute the given values into the formula:

    tan⁡(55∘)=h10\tan(55^\circ) = \frac{h}{10}

    Multiply both sides by 10 to solve for hh:

    h=10×tan⁡(55∘)h = 10 \times \tan(55^\circ)

    Using a calculator for tan⁡(55∘)\tan(55^\circ):

    h≈10×1.428148h \approx 10 \times 1.428148 h≈14.28148 mh \approx 14.28148 \text{ m}
  4. Round the answer to the nearest metre.

    h≈14 mh \approx 14 \text{ m}

    Comparing this to the given options:
    A. 7.0 m7.0 \text{ m}
    B. 8.0 m8.0 \text{ m}
    C. 6.0 m6.0 \text{ m}
    D. 14.0 m14.0 \text{ m}

    The correct option is D.
    The height of the pole is 14.0 m\boxed{\text{14.0 m}}.

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