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Graph the following linear equations by finding two points for each: a) y = -2x + 3 b) x + y = 5

Mathematics

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Answers

2 parts
a

Point 1: (0,3), Point 2: (1,1)\textbf{Point 1: } (0, 3), \textbf{ Point 2: } (1, 1)

b

Point 1: (0,5), Point 2: (5,0)\textbf{Point 1: } (0, 5), \textbf{ Point 2: } (5, 0)

Graph of y = −2x + 3

Use the left and right arrow keys to trace the curve, up and down to jump between key points, and plus and minus to zoom.

Key points of y = −2x + 3
Pointxy
y-intercept03
x-intercept1.50

Step-by-step solution

4 steps

Part a· 2 steps

For the equation y=−2x+3y = -2x + 3

  1. Find two points that satisfy the equation.

    • Let x=0x = 0:
    y=−2(0)+3y = -2(0) + 3 y=0+3y = 0 + 3 y=3y = 3

    This gives the point (0,3)(0, 3).

    • Let x=1x = 1:
    y=−2(1)+3y = -2(1) + 3 y=−2+3y = -2 + 3 y=1y = 1

    This gives the point (1,1)(1, 1).

  2. Plot the points $(0, 3)$ and $(1, 1)$ on a coordinate plane.

    Draw a straight line passing through these two points.
    The points for the graph are: Point 1: (0,3), Point 2: (1,1)\boxed{\textbf{Point 1: } (0, 3), \textbf{ Point 2: } (1, 1)}

Part b

Point 1: (0,5), Point 2: (5,0)\textbf{Point 1: } (0, 5), \textbf{ Point 2: } (5, 0)

For the equation x+y=5x + y = 5

  1. Find two points that satisfy the equation.

    • Let x=0x = 0:
    0+y=50 + y = 5 y=5y = 5

    This gives the point (0,5)(0, 5).

    • Let y=0y = 0:
    x+0=5x + 0 = 5 x=5x = 5

    This gives the point (5,0)(5, 0).

  2. Plot the points $(0, 5)$ and $(5, 0)$ on a coordinate plane.

    Draw a straight line passing through these two points.
    The points for the graph are: Point 1: (0,5), Point 2: (5,0)\boxed{\textbf{Point 1: } (0, 5), \textbf{ Point 2: } (5, 0)}

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