Find the greatest common divisor (GCD) of 144x3y2 and 81x1y4.

April 15, 2026Mathematics

ScanSolve AI Answer

April 15, 2026

Answer

2^4 \times 3^2 $$

Here are the solutions to the problems.

1) a) Step 1: Find the prime factorization of the numerical coefficients. $144 = 2^4 \times 3^2$ $81 = 3^4$ The greatest common divisor (GCD) of 144 and 81 is the product of the lowest powers of their common prime factors. $GCD(144, 81) = 3^2 = 9$

Step 2: Find the GCD of the variable parts. For $x$ : The terms are $x^3$ and $x^1$ . The lowest power is $x^1$ . For $y$ : The terms are $y^2

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Find the prime factorization of the numerical coefficients. 144 = 2^4 × 3^2 81 = 3^4 The greatest common divisor (GCD) of 144 and 81 is the product of the lowest powers of their common prime factors.

Asked on April 15, 2026Mathematics

This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

ScanSolve AI AnswerAnswered on April 15, 2026

Here are the solutions to the problems. 1) a) Step 1: Find the prime factorization of the numerical coefficients. 144 = 2^4 × 3^2 81 = 3^4 The greatest common divisor (GCD) of 144 and 81 is the product of the lowest powers of their common prime factors. GCD(144, 81) = 3^2 = 9 Step 2: Find the GCD of the variable parts. For x: The terms are x^3 and x^1. The lowest power is x^1. For y: The terms are $y^2