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Find the HCF of 18a2y and 27x2y2, and the sum of the prime factors of 180.
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20 stepsOkay, let's tackle the 'a' parts of those problems.
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The problem asks to find the Highest Common Factor (HCF) of and .
Find the prime factorization of the numerical coefficients
- $18 = 2 \times 3^2$ - $27 = 3^3$Identify the common prime factors and their lowest powers
- The common prime factor is 3. The lowest power of 3 is $3^2$. - HCF of 18 and 27 is $3^2 = 9$.Identify the common variables and their lowest powers
- For variable 'a', it appears only in $18a^2y$. - For variable 'x', it appears only in $27x^2y^2$. - For variable 'y', it appears in both terms. The lowest power of 'y' is $y^1$ (from $18a^2y$).Multiply the common numerical HCF by the common variables with their lowest powers.
The HCF is .
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The problem asks to find the sum of the prime factors of 180.
Find the prime factorization of 180.
- $180 = 18 \times 10$ - $18 = 2 \times 9 = 2 \times 3^2$ - $10 = 2 \times 5$Combine the prime factors
- $180 = (2 \times 3^2) \times (2 \times 5) = 2^2 \times 3^2 \times 5^1$.The distinct prime factors are 2, 3, and 5.
Find the sum of these distinct prime factors
- Sum = $2 + 3 + 5 = 10$.The sum of the prime factors of 180 is .
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The problem states that the sum of 8 and a certain number is equal to the product of the number and 3.
We need to find the number.
Let the certain number be .
Translate the statement into an equation
- "The sum of 8 and a certain number": $8 + x$ - "The product of the number and 3": $3x$ - "is equal to": $8 + x = 3x$Solve the equation for .
Subtract from both sides: - -
Divide by 2
- $x = \frac{8}{2}$ - $x = 4$The number is .
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The problem asks to round off 0.01256 to three significant figures.
Identify the significant figures.
Non-zero digits are always significant. Leading zeros (zeros before non-zero digits) are not significant. - In 0.01256, the first significant figure is 1. - The second significant figure is 2. - The third significant figure is 5.
Look at the digit immediately after the third significant figure, which is 6.
Since 6 is 5 or greater, round up the third significant figure (5).
- 5 becomes 6.Keep the leading zeros as placeholders for the decimal point.
The number rounded to three significant figures is .
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