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Identify the angle AYZ. This is the angle between the tangent XYZ and the chord AY.

Mathematics

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8 parts
a

∠ABY and ∠ACY\angle ABY \text{ and } \angle ACY

b

∠CAY and ∠CBY\angle CAY \text{ and } \angle CBY

c

∠BAY\angle BAY

d

∠BCY\angle BCY

e

58∘58^\circ

f

68∘68^\circ

g

125∘125^\circ

h

100∘100^\circ

Step-by-step solution

17 steps

Here are the solutions to the questions based on Fig. 12.31 and the Alternate Segment Theorem, which states that the angle between a tangent and a chord through the point of contact is equal to the angle in the alternate segment.

Part a· 2 steps

Name two angles equal to ∠AYZ\angle AYZ.

  1. Identify the angle ∠AYZ\angle AYZ.

    This is the angle between the tangent XYZXYZ and the chord AYAY.

  2. Apply the Alternate Segment Theorem.

    The angles in the alternate segment subtended by chord AYAY are ∠ABY\angle ABY and ∠ACY\angle ACY.

    ∠AYZ=∠ABY=∠ACY\angle AYZ = \angle ABY = \angle ACY

    The two angles are ∠ABY and ∠ACY\boxed{\angle ABY \text{ and } \angle ACY}.

Part b

∠CAY and ∠CBY\angle CAY \text{ and } \angle CBY

Name two angles equal to ∠CYX\angle CYX.

  1. Identify the angle ∠CYX\angle CYX.

    This is the angle between the tangent XYZXYZ and the chord CYCY.

  2. Apply the Alternate Segment Theorem.

    The angles in the alternate segment subtended by chord CYCY are ∠CAY\angle CAY and ∠CBY\angle CBY.

    ∠CYX=∠CAY=∠CBY\angle CYX = \angle CAY = \angle CBY

    The two angles are ∠CAY and ∠CBY\boxed{\angle CAY \text{ and } \angle CBY}.

Part c

∠BAY\angle BAY

Name an angle equal to ∠BYZ\angle BYZ.

  1. Identify the angle ∠BYZ\angle BYZ.

    This is the angle between the tangent XYZXYZ and the chord BYBY.

  2. Apply the Alternate Segment Theorem.

    The angle in the alternate segment subtended by chord BYBY is ∠BAY\angle BAY.

    ∠BYZ=∠BAY\angle BYZ = \angle BAY

    The angle is ∠BAY\boxed{\angle BAY}.

Part d

∠BCY\angle BCY

Name an angle equal to ∠BYX\angle BYX.

  1. Identify the angle ∠BYX\angle BYX.

    This is the angle between the tangent XYZXYZ and the chord BYBY.

  2. Apply the Alternate Segment Theorem.

    The angle in the alternate segment subtended by chord BYBY is ∠BCY\angle BCY.

    ∠BYX=∠BCY\angle BYX = \angle BCY

    The angle is ∠BCY\boxed{\angle BCY}.

Part e

58∘58^\circ

If ∠AYZ=58∘\angle AYZ = 58^\circ what is ∠ACY\angle ACY?

  1. From part a), we know that ∠AYZ=∠ACY\angle AYZ = \angle ACY.

  2. Substitute the given value.

    ∠ACY=58∘\angle ACY = 58^\circ

    The angle is 58∘\boxed{58^\circ}.

Part f

68∘68^\circ

If ∠BCY=112∘\angle BCY = 112^\circ what is ∠BYZ\angle BYZ?

  1. From part d), we know that ∠BYX=∠BCY\angle BYX = \angle BCY.

    ∠BYX=112∘\angle BYX = 112^\circ
  2. Angles on a straight line sum to 180∘180^\circ.

    ∠BYX\angle BYX and ∠BYZ\angle BYZ are adjacent angles on the straight line XYZXYZ.

    ∠BYX+∠BYZ=180∘\angle BYX + \angle BYZ = 180^\circ
  3. Substitute the value of ∠BYX\angle BYX and solve for ∠BYZ\angle BYZ.

    112∘+∠BYZ=180∘112^\circ + \angle BYZ = 180^\circ ∠BYZ=180∘−112∘\angle BYZ = 180^\circ - 112^\circ ∠BYZ=68∘\angle BYZ = 68^\circ

    The angle is 68∘\boxed{68^\circ}.

Part g

125∘125^\circ

If ∠BCY=125∘\angle BCY = 125^\circ what is ∠BYX\angle BYX?

  1. From part d), we know that ∠BYX=∠BCY\angle BYX = \angle BCY.

  2. Substitute the given value.

    ∠BYX=125∘\angle BYX = 125^\circ

    The angle is 125∘\boxed{125^\circ}.

Part h

100∘100^\circ

If ∠BYZ=100∘\angle BYZ = 100^\circ what is ∠BAY\angle BAY?

  1. From part c), we know that ∠BYZ=∠BAY\angle BYZ = \angle BAY.

  2. Substitute the given value.

    ∠BAY=100∘\angle BAY = 100^\circ

    The angle is 100∘\boxed{100^\circ}.

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