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An arc AB of a sector of a circle subtends an angle 140° at the centre of the circle. Find the angle subtended by the arc from the circumference.

Mathematics

ScanSolve AI Answer

Answer

70∘70^\circ

Step-by-step solution

5 steps
  1. Identify the central angle.

    The chord AB subtends an angle of 140∘140^\circ at the center O of the circle.

  2. State the theorem.

    The angle subtended by an arc at the center of the circle is twice the angle subtended by the same arc at a point on the remaining circumference:
    θcenter=2×θcircumference\theta_\text{center} = 2 \times \theta_\text{circumference}.

  3. Set up the formula for the angle at the circumference.

    θcircumference=12θcenter\theta_\text{circumference} = \frac{1}{2} \theta_\text{center}
  4. Substitute the given value.

    θcircumference=12×140∘\theta_\text{circumference} = \frac{1}{2} \times 140^\circ
  5. Simplify.

    θcircumference=70∘\theta_\text{circumference} = 70^\circ

    Final answer: 70∘\boxed{70^\circ}

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