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Identify the coefficient of the x2 term.

Mathematics

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Answers

2 parts
b
-1
c
25

Step-by-step solution

7 steps

Here's the solution for the given function f(x)=−x2−2x+24f(x) = -x^2 - 2x + 24.

Part a· 3 steps

Will the function have a minimum or maximum?

  1. Identify the coefficient of the x2x^2 term.

    For the function f(x)=−x2−2x+24f(x) = -x^2 - 2x + 24, the coefficient of x2x^2 is a=−1a = -1.

  2. Determine if the parabola opens upwards or downwards.

    Since a=−1a = -1 is negative (a<0a < 0), the parabola opens downwards.

  3. Conclude whether it's a minimum or maximum.

    A parabola that opens downwards has a highest point, which is a maximum.

    The function will have a maximum.

Part b-1

Determine the x-coordinates of the turning point.

  1. Use the formula for the x-coordinate of the turning point (vertex) of a parabola f(x)=ax2+bx+cf(x) = ax^2 + bx + c.

    The formula is x=−b2ax = -\frac{b}{2a}.
    From the function f(x)=−x2−2x+24f(x) = -x^2 - 2x + 24, we have a=−1a = -1 and b=−2b = -2.

  2. Substitute the values of aa and bb into the formula.

    x=−−22(−1)x = -\frac{-2}{2(-1)} x=−−2−2x = -\frac{-2}{-2} x=−(1)x = -(1) x=−1x = -1

    The x-coordinate of the turning point is −1\boxed{-1}.

Part c25

Determine the y-coordinates of the turning point.

  1. Substitute the x-coordinate found in part b) into the original function f(x)f(x).

    We found x=−1x = -1.

    f(x)=−x2−2x+24f(x) = -x^2 - 2x + 24 f(−1)=−(−1)2−2(−1)+24f(-1) = -(-1)^2 - 2(-1) + 24
  2. Calculate the value of f(−1)f(-1).

    f(−1)=−(1)+2+24f(-1) = -(1) + 2 + 24 f(−1)=−1+2+24f(-1) = -1 + 2 + 24 f(−1)=1+24f(-1) = 1 + 24 f(−1)=25f(-1) = 25

    The y-coordinate of the turning point is 25\boxed{25}.

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