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The rationalising factor of sqrt(5) + sqrt(3) is:

Mathematics

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A

Step-by-step solution

11 steps
  1. The rationalising factor of 5+3\sqrt{5} + \sqrt{3} is:
  1. Identify the expression to be rationalized.

    The expression is 5+3\sqrt{5} + \sqrt{3}.

  2. Determine the rationalizing factor.

    For an expression of the form a+b\sqrt{a} + \sqrt{b}, its rationalizing factor is a−b\sqrt{a} - \sqrt{b}.
    Therefore, the rationalizing factor of 5+3\sqrt{5} + \sqrt{3} is 5−3\sqrt{5} - \sqrt{3}.

    The correct option is A.

    A) 5−3\boxed{\text{A) } \sqrt{5} - \sqrt{3}}
    1. In a cricket match two batsmen together scored 181 runs. The linear equation form for the statement is:
  3. Define variables for the runs scored by each batsman.

    Let xx be the runs scored by the first batsman.
    Let yy be the runs scored by the second batsman.

  4. Formulate the equation based on the given information.

    "Two batsmen together scored 181 runs" means the sum of their runs is 181.
    So, x+y=181x + y = 181.

    The correct option is C.

    C) x+y=181\boxed{\text{C) } x + y = 181}
    1. In a parallelogram, if the adjacent angles are in the ratio 2:3, then the measure of these adjacent angles are:
  5. Recall the property of adjacent angles in a parallelogram.

    Adjacent angles in a parallelogram are supplementary, meaning their sum is 180∘180^\circ.

  6. Set up an equation based on the given ratio.

    Let the adjacent angles be 2k2k and 3k3k.

    2k+3k=180∘2k + 3k = 180^\circ
  7. Solve for kk.

    5k=180∘5k = 180^\circ k=180∘5k = \frac{180^\circ}{5} k=36∘k = 36^\circ
  8. Calculate the measure of each angle.

    First angle: 2k=2×36∘=72∘2k = 2 \times 36^\circ = 72^\circ
    Second angle: 3k=3×36∘=108∘3k = 3 \times 36^\circ = 108^\circ

    The correct option is B.

    B) 72∘ and 108∘\boxed{\text{B) } 72^\circ \text{ and } 108^\circ}
    1. If the radius of a sphere is 2r2r, then its volume will be:
  9. Write down the formula for the volume of a sphere.

    The volume VV of a sphere with radius RR is given by:

    V=43πR3V = \frac{4}{3}\pi R^3
  10. Substitute the given radius into the formula.

    Given radius R=2rR = 2r.

    V=43π(2r)3V = \frac{4}{3}\pi (2r)^3
  11. Simplify the expression.

    V=43π(23r3)V = \frac{4}{3}\pi (2^3 r^3) V=43π(8r3)V = \frac{4}{3}\pi (8 r^3) V=4×83πr3V = \frac{4 \times 8}{3}\pi r^3 V=323πr3V = \frac{32}{3}\pi r^3

    The correct option is D.

    D) 323πr3\boxed{\text{D) } \frac{32}{3}\pi r^3}
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