Step 1: Identify the given information for the cubic polynomial. Let the zeroes of the cubic polynomial be $\alpha, \beta, \gamma$. The general form of a cubic polynomial is $P(x) = ax^3 + bx^2 + cx + d$. The relationships between the zeroes and coefficients are: Sum of zeroes: $\alpha + \beta + \gamma = -\frac{b}{a}$ Sum of the product of zeroes taken two at a time: $\alpha\beta + \beta\gamma + \gamma\alpha = \frac{c}{a}$ Product of zeroes: $\alpha\beta\gamma = -\frac{d}{a}$ From the problem statement: Sum of zeroes $= -2$ Sum of the product of its zeroes taken two at a time $= 7$ Product of its zeroes $= 16$ Step 2: Set up the equations based on the given values. We can assume $a=1$ to find a cubic polynomial. So, we have: $$-\frac{b}{1} = -2 \implies b = 2$$ $$\frac{c}{1} = 7 \implies c = 7$$ $$-\frac{d}{1} = 16 \implies d = -16$$ Step 3: Form the cubic polynomial. Substitute the values of $a, b, c, d$ into the general form $P(x) = ax^3 + bx^2 + cx + d$. $$P(x) = 1x^3 + 2x^2 + 7x - 16$$ $$P(x) = x^3 + 2x^2 + 7x - 16$$ The cubic polynomial is $\boxed{x^3 + 2x^2 + 7x - 16}$.