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Identify the given information for the cubic polynomial.

Mathematics

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Answer

x3+2x2+7x−16x^3 + 2x^2 + 7x - 16

Step-by-step solution

3 steps
  1. Identify the given information for the cubic polynomial.

    Let the zeroes of the cubic polynomial be α,β,γ\alpha, \beta, \gamma.
    The general form of a cubic polynomial is P(x)=ax3+bx2+cx+dP(x) = ax^3 + bx^2 + cx + d.
    The relationships between the zeroes and coefficients are:
    Sum of zeroes: α+β+γ=−ba\alpha + \beta + \gamma = -\frac{b}{a}
    Sum of the product of zeroes taken two at a time: αβ+βγ+γα=ca\alpha\beta + \beta\gamma + \gamma\alpha = \frac{c}{a}
    Product of zeroes: αβγ=−da\alpha\beta\gamma = -\frac{d}{a}

    From the problem statement:
    Sum of zeroes =−2= -2
    Sum of the product of its zeroes taken two at a time =7= 7
    Product of its zeroes =16= 16

  2. Set up the equations based on the given values.

    We can assume a=1a=1 to find a cubic polynomial.
    So, we have:

    −b1=−2  ⟹  b=2-\frac{b}{1} = -2 \implies b = 2 c1=7  ⟹  c=7\frac{c}{1} = 7 \implies c = 7 −d1=16  ⟹  d=−16-\frac{d}{1} = 16 \implies d = -16
  3. Form the cubic polynomial.

    Substitute the values of a,b,c,da, b, c, d into the general form P(x)=ax3+bx2+cx+dP(x) = ax^3 + bx^2 + cx + d.

    P(x)=1x3+2x2+7x−16P(x) = 1x^3 + 2x^2 + 7x - 16 P(x)=x3+2x2+7x−16P(x) = x^3 + 2x^2 + 7x - 16

    The cubic polynomial is x3+2x2+7x−16x^3 + 2x^2 + 7x - 16.

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