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Identify the names of the triangles drawn below.

Mathematics

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Hapa kuna masuluhisho ya maswali uliyotuma:

25. (a) (ii) the distance covered by the wheel after it makes 100 revolutions on a flat surface.

Kutoka jibu lililopita, mzingo wa gurudumu (umbali unaofunikwa kwa mzunguko mmoja) ni 132 cm132 \text{ cm}.

  1. Kokotoa umbali wote uliopitiwa.

    Umbali wote = Mzingo wa gurudumu ×\times Idadi ya mizunguko.

    Umbali=132 cm×100\text{Umbali} = 132 \text{ cm} \times 100 Umbali=13200 cm\text{Umbali} = 13200 \text{ cm}

    Umbali uliopitiwa na gurudumu ni:

    13200 cm\boxed{\text{13200 cm}}

    25. (b) Calculate the height of a cylindrical candle whose radius is 7cm and has a volume of 770cm³.

    Fomula ya ujazo wa silinda ni V=πr2hV = \pi r^2 h.
    Tunapewa:
    Radiasi r=7 cmr = 7 \text{ cm}
    Ujazo V=770 cm3V = 770 \text{ cm}^3
    Tunatumia π=227\pi = \frac{22}{7}.

  2. Badilisha maadili kwenye fomula ya ujazo.

    770 cm3=227×(7 cm)2×h770 \text{ cm}^3 = \frac{22}{7} \times (7 \text{ cm})^2 \times h 770 cm3=227×49 cm2×h770 \text{ cm}^3 = \frac{22}{7} \times 49 \text{ cm}^2 \times h
  3. Rahisisha na tafuta urefu hh.

    770 cm3=22×7 cm2×h770 \text{ cm}^3 = 22 \times 7 \text{ cm}^2 \times h 770 cm3=154 cm2×h770 \text{ cm}^3 = 154 \text{ cm}^2 \times h h=770 cm3154 cm2h = \frac{770 \text{ cm}^3}{154 \text{ cm}^2} h=5 cmh = 5 \text{ cm}

    Urefu wa mshumaa ni:

    5 cm\boxed{\text{5 cm}}

    25. (c) When Medrine fell sick, her temperature rose to 39.50c. What was her temperature in Kelvin?

    Ili kubadilisha halijoto kutoka Selsiasi kwenda Kelvin, tunatumia fomula TK=TC+273.15T_K = T_C + 273.15.
    Halijoto katika Selsiasi TC=39.50∘CT_C = 39.50^{\circ}\text{C}.

  4. Badilisha halijoto ya Selsiasi kuwa Kelvin.

    TK=39.50+273.15T_K = 39.50 + 273.15 TK=312.65 KT_K = 312.65 \text{ K}

    Halijoto ya Medrine katika Kelvin ilikuwa:

    312.65 K\boxed{\text{312.65 K}}

    25. (c) Identify the names of the triangles drawn below.

    Hapa kuna majina sahihi ya pembetatu:

    • Pembetatu ya kwanza (yenye alama tatu za mistari sawa): Pembetatu pacha (Equilateral triangle)
    • Pembetatu ya pili (yenye alama ya pembe mraba): Pembetatu mraba (Right-angled triangle)
    • Pembetatu ya tatu (yenye pembe 30∘,110∘,40∘30^{\circ}, 110^{\circ}, 40^{\circ}): Pembetatu tofauti (Scalene triangle)
    • Pembetatu ya nne (yenye alama mbili za mistari sawa): Pembetatu pacha miguu miwili (Isosceles triangle)

    26. (a) Philip bought a refrigerator for Sh.24000. He later sold it at a loss of 30%. How much did he sell the refrigerator?

    Bei ya kununua = Sh. 24000.
    Hasara = 30%.

  5. Kokotoa kiasi cha hasara.

    Hasara=30% ya Sh. 24000\text{Hasara} = 30\% \text{ ya Sh. } 24000 Hasara=30100×24000\text{Hasara} = \frac{30}{100} \times 24000 Hasara=Sh. 7200\text{Hasara} = \text{Sh. } 7200
  6. Kokotoa bei ya kuuza.

    Bei ya kuuza = Bei ya kununua - Hasara.

    Bei ya kuuza=Sh. 24000−Sh. 7200\text{Bei ya kuuza} = \text{Sh. } 24000 - \text{Sh. } 7200 Bei ya kuuza=Sh. 16800\text{Bei ya kuuza} = \text{Sh. } 16800

    Philip aliuza friji kwa:

    Sh. 16800\boxed{\text{Sh. 16800}}

    26. (b) Find the value of the angles marked with letters.

    Katika mchoro, mistari miwili ya juu ni sambamba.

  7. Tafuta thamani ya xx.

    Pembe xx na pembe ya 40∘40^{\circ} ni pembe mbadala za ndani (alternate interior angles).
    Kwa hiyo, x=40∘x = 40^{\circ}.

  8. Tafuta thamani ya zz.

    Pembe zz na pembe ya 70∘70^{\circ} ni pembe mbadala za ndani (alternate interior angles).
    Kwa hiyo, z=70∘z = 70^{\circ}.

  9. Tafuta thamani ya kk.

    Pembe xx, zz, na kk ni pembe za ndani za pembetatu. Jumla ya pembe za ndani za pembetatu ni 180∘180^{\circ}.

    x+z+k=180∘x + z + k = 180^{\circ} 40∘+70∘+k=180∘40^{\circ} + 70^{\circ} + k = 180^{\circ} 110∘+k=180∘110^{\circ} + k = 180^{\circ} k=180∘−110∘k = 180^{\circ} - 110^{\circ} k=70∘k = 70^{\circ}

    Thamani za pembe ni:

    x=40∘,z=70∘,k=70∘\boxed{x = 40^{\circ}, z = 70^{\circ}, k = 70^{\circ}}

    27. A saleswoman was paid a monthly salary of Sh.9000. She was also paid a commission of 10% for all the goods she sold above Sh.10000. In one month, she sold goods worth Sh.25000. What did she earn at the end of that month?

    Mshahara wa kila mwezi = Sh. 9000.
    Mauzo yote = Sh. 25000.
    Tume = 10% kwa mauzo yanayozidi Sh. 10000.

  10. Kokotoa mauzo yanayostahiki tume.

    Mauzo yanayostahiki tume=Mauzo yote−Kiasi kisichostahiki tume\text{Mauzo yanayostahiki tume} = \text{Mauzo yote} - \text{Kiasi kisichostahiki tume} Mauzo yanayostahiki tume=Sh. 25000−Sh. 10000\text{Mauzo yanayostahiki tume} = \text{Sh. } 25000 - \text{Sh. } 10000 Mauzo yanayostahiki tume=Sh. 15000\text{Mauzo yanayostahiki tume} = \text{Sh. } 15000
  11. Kokotoa kiasi cha tume.

    Tume=10% ya Sh. 15000\text{Tume} = 10\% \text{ ya Sh. } 15000 Tume=10100×15000\text{Tume} = \frac{10}{100} \times 15000 Tume=Sh. 1500\text{Tume} = \text{Sh. } 1500
  12. Kokotoa jumla ya mapato.

    Jumla ya mapato=Mshahara wa kila mwezi+Tume\text{Jumla ya mapato} = \text{Mshahara wa kila mwezi} + \text{Tume} Jumla ya mapato=Sh. 9000+Sh. 1500\text{Jumla ya mapato} = \text{Sh. } 9000 + \text{Sh. } 1500 Jumla ya mapato=Sh. 10500\text{Jumla ya mapato} = \text{Sh. } 10500

    Mwanamke huyo aliingiza jumla ya:

    Sh. 10500\boxed{\text{Sh. 10500}}

    28. In a wedding party, the number of men, women and children were in the ratio 2:3:5 respectively. If 60 women attended the wedding,

    Uwiano wa wanaume : wanawake : watoto = 2 : 3 : 5.
    Idadi ya wanawake = 60.

  13. Tafuta thamani ya sehemu moja ya uwiano.

    Sehemu ya wanawake katika uwiano ni 3.
    Ikiwa sehemu 3 zinawakilisha wanawake 60, basi sehemu 1 inawakilisha:

    Sehemu 1=603=20 watu\text{Sehemu 1} = \frac{60}{3} = 20 \text{ watu}

    28. (i) how many children attended the wedding?

    Sehemu ya watoto katika uwiano ni 5.

    Idadi ya watoto=5×Sehemu 1\text{Idadi ya watoto} = 5 \times \text{Sehemu 1} Idadi ya watoto=5×20=100 watoto\text{Idadi ya watoto} = 5 \times 20 = 100 \text{ watoto}

    Idadi ya watoto waliohudhuria harusi ni:

    100 watoto\boxed{\text{100 watoto}}

    28. (ii) how many men attended the wedding?

    Sehemu ya wanaume katika uwiano ni 2.

    Idadi ya wanaume=2×Sehemu 1\text{Idadi ya wanaume} = 2 \times \text{Sehemu 1} Idadi ya wanaume=2×20=40 wanaume\text{Idadi ya wanaume} = 2 \times 20 = 40 \text{ wanaume}

    Idadi ya wanaume waliohudhuria harusi ni:

    40 wanaume\boxed{\text{40 wanaume}}

    28. (iii) how many more children than men attended the wedding?

    Tofauti kati ya idadi ya watoto na wanaume.

    Tofauti=Idadi ya watoto−Idadi ya wanaume\text{Tofauti} = \text{Idadi ya watoto} - \text{Idadi ya wanaume} Tofauti=100−40=60\text{Tofauti} = 100 - 40 = 60

    Watoto walikuwa wengi kuliko wanaume kwa:

    60\boxed{\text{60}}
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