If the second Tuesday of a month is the 7th, what day of the week is the 21st of that month?

Mathematics
If the second Tuesday of a month is the 7th, what day of the week is the 21st of that month?

ScanSolve AI Answer

Answer

6\ cm

Step 1: Identify the right triangle and the Pythagoras theorem.
Triangle ABC is right-angled at C, with hypotenuse AB.

AB2=AC2+BC2AB^{2} = AC^{2} + BC^{2}

Step 2: Substitute the given lengths.
AB = 10 cm, AC = 8 cm.

(10 cm)2=(8 cm)2+BC2(10\ cm)^{2} = (8\ cm)^{2} + BC^{2}

Step 3: Calculate the squares.

100 cm2=64 cm2+BC2100\ cm^{2} = 64\ cm^{2} + BC^{2}

Step 4: Isolate BC2BC^{2}.

BC2=100 cm2−64 cm2BC^{2} = 100\ cm^{2} - 64\ cm^{2} BC2=36 cm2BC^{2} = 36\ cm^{2}

Step 5: Take the square root (positive length).

BC=36 cm2BC = \sqrt{36\ cm^{2}} BC=6 cmBC = 6\ cm

6\ \text{cm}

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Identify the right triangle and the Pythagoras theorem. Triangle ABC is right-angled at C, with hypotenuse AB.

If the second Tuesday of a month is the 7th, what day of the week is the 21st of that month?
Mathematics

This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

ScanSolve AI Answer
Step 1: Identify the right triangle and the Pythagoras theorem. Triangle ABC is right-angled at C, with hypotenuse AB. AB^2 = AC^2 + BC^2 Step 2: Substitute the given lengths. AB = 10 cm, AC = 8 cm. (10\ cm)^2 = (8\ cm)^2 + BC^2 Step 3: Calculate the squares. 100\ cm^2 = 64\ cm^2 + BC^2 Step 4: Isolate BC^2. BC^2 = 100\ cm^2 - 64\ cm^2 BC^2 = 36\ cm^2 Step 5: Take the square root (positive length). BC = sqrt(36\ cm)^2 BC = 6\ cm 6\ cm