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If (2a-b)/(6a-5b) = -3, find 5a:2b.

Mathematics

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Answer

C) 2 : 1\text{C) 2 : 1}

Step-by-step solution

4 steps
  1. Simplify the given equation to find the relationship between aa and bb.

    We are given the equation:

    2a−b6a−5b=−3\frac{2a-b}{6a-5b} = -3

    Multiply both sides by (6a−5b)(6a-5b):

    2a−b=−3(6a−5b)2a-b = -3(6a-5b)

    Distribute the −3-3 on the right side:

    2a−b=−18a+15b2a-b = -18a + 15b
  2. Rearrange the terms to group aa terms and bb terms.

    Add 18a18a to both sides:

    2a+18a−b=15b2a + 18a - b = 15b 20a−b=15b20a - b = 15b

    Add bb to both sides:

    20a=15b+b20a = 15b + b 20a=16b20a = 16b
  3. Express the ratio a:ba:b.

    Divide both sides by bb and by 20:

    ab=1620\frac{a}{b} = \frac{16}{20}

    Simplify the fraction by dividing the numerator and denominator by their greatest common divisor, which is 4:

    ab=16÷420÷4=45\frac{a}{b} = \frac{16 \div 4}{20 \div 4} = \frac{4}{5}

    So, the ratio a:ba:b is 4:54:5.

  4. Calculate the required ratio $5a:2b$.

    We need to find the value of 5a2b\frac{5a}{2b}. We can rewrite this as:

    5a2b=52×ab\frac{5a}{2b} = \frac{5}{2} \times \frac{a}{b}

    Substitute the value of ab\frac{a}{b} from Step 3:

    5a2b=52×45\frac{5a}{2b} = \frac{5}{2} \times \frac{4}{5}

    Multiply the fractions:

    5a2b=5×42×5=2010\frac{5a}{2b} = \frac{5 \times 4}{2 \times 5} = \frac{20}{10} 5a2b=2\frac{5a}{2b} = 2

    This means the ratio 5a:2b5a:2b is 2:12:1.

    The final answer is C) 2 : 1\text{C) 2 : 1}.

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