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If 42x−3 = 2^x-3, find the value of x.

Mathematics

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Here are the solutions to the questions:

1. If 42x−3=2x−34^{2x-3} = 2^{x-3}, find the value of xx.

  1. Express both sides of the equation with the same base.

    Since 4=224 = 2^2, we can rewrite 42x−34^{2x-3} as (22)2x−3(2^2)^{2x-3}.

    (22)2x−3=22(2x−3)=24x−6(2^2)^{2x-3} = 2^{2(2x-3)} = 2^{4x-6}

    The equation becomes:

    24x−6=2x−32^{4x-6} = 2^{x-3}
  2. Equate the exponents.

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