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Find the value of x 32(x+1) = 4(2−x)

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3 parts
4

x=−17x = -\frac{1}{7}

5
0.1966
6

2x+4yx2−y2\frac{2x + 4y}{x^2 - y^2}

Step-by-step solution

12 steps

Haya Omar, tuendelee na maswali haya.

Part 4· 4 steps

  1. Andika namba zote kwa msingi mmoja.

    Tunajua kuwa 32=2532 = 2^5 na 4=224 = 2^2.
    Badilisha hizi kwenye mlinganyo:

    (25)(x+1)=(22)(2−x)(2^5)^{(x+1)} = (2^2)^{(2-x)}
  2. Tumia sheria ya vipeo (am)n=amn(a^m)^n = a^{mn}.

    25(x+1)=22(2−x)2^{5(x+1)} = 2^{2(2-x)} 25x+5=24−2x2^{5x+5} = 2^{4-2x}
  3. Linganisha vipeo kwa sababu misingi ni sawa.

    5x+5=4−2x5x+5 = 4-2x
  4. Tatua kwa xx.

    Kusanya xx upande mmoja na namba upande mwingine:

    5x+2x=4−55x + 2x = 4 - 5 7x=−17x = -1 x=−17x = -\frac{1}{7} x=−17\boxed{x = -\frac{1}{7}}

Part 50.1966

  1. Weka usemi kama YY na chukua logariti pande zote mbili.

    Y=1.794×0.060814.343Y = \sqrt[3]{\frac{1.794 \times 0.0608}{14.34}} log⁡Y=log⁡((1.794×0.060814.34)13)\log Y = \log \left( \left(\frac{1.794 \times 0.0608}{14.34}\right)^{\frac{1}{3}} \right) log⁡Y=13(log⁡(1.794)+log⁡(0.0608)−log⁡(14.34))\log Y = \frac{1}{3} \left( \log(1.794) + \log(0.0608) - \log(14.34) \right)
  2. Tafuta logariti za namba kwa kutumia jedwali la logariti.

    • log⁡(1.794)=0.2538\log(1.794) = 0.2538
    • log⁡(0.0608)=2ˉ.7839\log(0.0608) = \bar{2}.7839 (au −2+0.7839-2 + 0.7839)
    • log⁡(14.34)=1.1565\log(14.34) = 1.1565
  3. Badilisha thamani za logariti kwenye mlinganyo na ufanye hesabu.

    log⁡Y=13(0.2538+2ˉ.7839−1.1565)\log Y = \frac{1}{3} (0.2538 + \bar{2}.7839 - 1.1565) log⁡Y=13(0.2538−2+0.7839−1.1565)\log Y = \frac{1}{3} (0.2538 - 2 + 0.7839 - 1.1565) log⁡Y=13(−2.1188)\log Y = \frac{1}{3} (-2.1188) log⁡Y=−0.706266...\log Y = -0.706266...
  4. Andika upya log⁡Y\log Y kwa mantisa chanya na utafute antilogariti.

    log⁡Y=−1+(1−0.706266...)=1ˉ.2937\log Y = -1 + (1 - 0.706266...) = \bar{1}.2937

    Tafuta antilog ya 1ˉ.2937\bar{1}.2937:

    Y=antilog(1ˉ.2937)Y = \text{antilog}(\bar{1}.2937) Y=10−1×100.2937Y = 10^{-1} \times 10^{0.2937} Y≈0.1×1.966Y \approx 0.1 \times 1.966 Y≈0.1966Y \approx 0.1966 0.1966\boxed{0.1966}

Part 6

2x+4yx2−y2\frac{2x + 4y}{x^2 - y^2}

  1. Tafuta kigawo cha kawaida (common denominator) cha sehemu hizo.

    Kigawo cha kawaida ni (x−y)(x+y)(x-y)(x+y).

    3x−y−1x+y=3(x+y)(x−y)(x+y)−1(x−y)(x−y)(x+y)\frac{3}{x-y} - \frac{1}{x+y} = \frac{3(x+y)}{(x-y)(x+y)} - \frac{1(x-y)}{(x-y)(x+y)}
  2. Unganisha namba za juu (numerators) juu ya kigawo kimoja.

    3(x+y)−1(x−y)(x−y)(x+y)\frac{3(x+y) - 1(x-y)}{(x-y)(x+y)}
  3. Panua na kurahisisha namba ya juu.

    3x+3y−x+y(x−y)(x+y)\frac{3x + 3y - x + y}{(x-y)(x+y)} 2x+4y(x−y)(x+y)\frac{2x + 4y}{(x-y)(x+y)}
  4. Unaweza pia kurahisisha kigawo kwa kutumia tofauti ya miraba (a2−b2=(a−b)(a+b)a^2 - b^2 = (a-b)(a+b)).

    2x+4yx2−y2\frac{2x + 4y}{x^2 - y^2} 2x+4yx2−y2\boxed{\frac{2x + 4y}{x^2 - y^2}}
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