If alpha and beta are the roots of x2 + x + 1 = 0, find p if the roots of x2 + px + q = 0 are (alpha)/(beta) and (beta)/(alpha).

Given the equation $x^2 + x + 1 = 0$, with roots $\alpha$ and $\beta$.
The sum of the roots is $\alpha + \beta = -\frac{1}{1} = -1$.
The product of the roots is $\alpha \beta = \frac{1}{1} = 1$.

Given the equation $x^2 + px + q = 0$, with roots $\frac{\alpha}{\beta}$ and $\frac{\beta}{\alpha}$.
The sum of these roots is $\frac{\alpha}{\beta} + \frac{\beta}{\alpha} = -p$.

We know that $\alpha^2 + \beta^2 = (\alpha + \beta)^2 - 2\alpha\beta$.
Substitute the values from Step 1:

Now substitute this back into the expression for the sum of the roots:

From Step 2, we have $\frac{\alpha}{\beta} + \frac{\beta}{\alpha} = -p$.
From Step 3, we found that $\frac{\alpha}{\beta} + \frac{\beta}{\alpha} = -1$.
Therefore,

The value of $p$ is 1. This corresponds to option (B).

The final answer is $\text{(B) } 1$.