This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.
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Here are the solutions to the questions: Question 37: If Owawa makes 7200 revolution in 5 hours, how many revolution does it make per minute? Step 1: Identify the total revolutions and total time. Total revolutions = 7200 Total time = 5 hours Step 2: Convert the total time from hours to minutes. There are 60 minutes in 1 hour. 5 hours × 60 minuteshour = 300 minutes Step 3: Calculate the revolutions per minute. Revolutions per minute = Total revolutionsTotal time in minutes Revolutions per minute = (7200)/(300) = 24 Owawa makes 24 revolutions per minute. The correct option is (b). b) 24 Question 38: The average score of 30 students in a Mathematics test is 6. If 28 out of 30 students scored a sum of 160 marks, find the average mark of the two remaining students. Step 1: Calculate the total score of all 30 students. Total number of students = 30 Average score of 30 students = 6 Total score = Average score × Number of students Total score = 6 × 30 = 180 Step 2: Identify the sum of scores for the 28 students. Sum of scores for 28 students = 160 Step 3: Calculate the sum of scores for the remaining students. Number of remaining students = 30 - 28 = 2 Sum of scores for remaining 2 students = Total score - Sum of scores for 28 students Sum of scores for remaining 2 students = 180 - 160 = 20 Step 4: Calculate the average mark of the two remaining students. Average mark = Sum of scores for remaining 2 studentsNumber of remaining students Average mark = (20)/(2) = 10 The average mark of the two remaining students is 10. The correct option is (d). d) 10 Question 39: Find the simple interest on N280 for 2(1)/(2) years at 3% per annum. Step 1: Identify the principal, rate, and time. Principal (P) = N280 Rate (R) = 3% per annum = (3)/(100) = 0.03 Time (T) = 2(1)/(2) years = 2.5 years Step 2: Use the formula for simple interest. Simple Interest (SI) = P × R × T Step 3: Substitute the values and calculate the simple interest. SI = 280 × 0.03 × 2.5 SI = 280 × 0.075 SI = 21 The simple interest is N21. Step 4: Since N21 is not an option, and N301 (option d) is the total amount (Principal + Simple Interest), we assume the question implicitly asks for the total amount. Amount = Principal + Simple Interest Amount = N280 + N21 = N301 The total amount after 2(1)/(2) years is N301. The correct option is (d). d) N301 Question 40: Find the increase of N240 by ratio 3:5. Step 1: Interpret the ratio. The phrase "increase of N240 by ratio 3:5" means that the original amount (N240) corresponds to the first part of the ratio (3), and the new amount corresponds to the second part (5). Let the original amount be A_o = N240. Let the new amount be A_n. The ratio of original to new is 3:5. (A_o)/(A_n) = (3)/(5) Step 2: Calculate the new amount. (240)/(A_n) = (3)/(5) 3 × A_n = 240 × 5 3 × A_n = 1200 A_n = (1200)/(3) A_n = 400 The new amount after the increase is N400. Step 3: The question asks for "the increase". The actual increase is 400 - 240 = 160. However, N160 is not an option, while N400 is an option. This suggests the question is asking for the new value after the increase, rather than the amount of the increase itself. The correct option is (c). c) 400 Question 41: Find the area of the trapezium below. Step 1: Identify the dimensions of the trapezium from the figure. The figure shows a right-angled trapezium. The parallel sides are the top and bottom horizontal lines. Length of the top parallel side (a) = 24 cm. Length of the bottom parallel side (b) = 6 cm + 24 cm = 30 cm. The height (h) is the perpendicular distance between the parallel sides, which is the vertical line on the right = 10 cm. Step 2: Use the formula for the area of a trapezium. Area = (1)/(2) (a+b)h Step 3: Substitute the values and calculate the area. Area = (1)/(2) (24 cm + 30 cm) × 10 cm Area = (1)/(2) (54 cm) × 10 cm Area = 27 cm × 10 cm Area = 270 cm^2 The area of the trapezium is 270 cm^2. The correct option is (c). c) 270 cm^2 Last free one today — make it count tomorrow, or type /upgrade for unlimited.