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A fan makes 2000 rotations in 4 seconds. Calculate its angular frequency. Options are: A) 500 rad/sec B) 1000 rad/sec C) 500pi rad/sec D) 1000pi rad/sec

Physics

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Step-by-step solution

6 steps

This question asks for the angular frequency of a fan.

  1. Identify the given information.

    • Number of rotations (NN) = 2000 rotations
    • Time (tt) = 4 seconds
  2. Calculate the linear frequency (ff).

    Linear frequency is the number of rotations per unit time.

    f=Number of rotationsTimef = \frac{\text{Number of rotations}}{\text{Time}} f=2000 rotations4 sf = \frac{2000 \text{ rotations}}{4 \text{ s}} f=500 Hzf = 500 \text{ Hz}
  3. Calculate the angular frequency (ω\omega).

    Angular frequency is related to linear frequency by the formula:

    ω=2πf\omega = 2\pi f

    Substitute the value of ff:

    ω=2π(500 Hz)\omega = 2\pi (500 \text{ Hz}) ω=1000πRadsec\omega = 1000\pi \frac{\text{Rad}}{\text{sec}}
  4. Compare with the given options.

    The calculated angular frequency is 1000πRadsec1000\pi \frac{\text{Rad}}{\text{sec}}. However, this value is not among the provided options. It is highly probable that there is a typo in the question, and the number of rotations should have been 200 instead of 2000 to match one of the options.

  5. Recalculate with the likely intended value (assuming a typo).

    If the number of rotations (NN) was 200 rotations:

    f=200 rotations4 sf = \frac{200 \text{ rotations}}{4 \text{ s}} f=50 Hzf = 50 \text{ Hz}

    Then, the angular frequency would be:

    ω=2π(50 Hz)\omega = 2\pi (50 \text{ Hz}) ω=100πRadsec\omega = 100\pi \frac{\text{Rad}}{\text{sec}}
  6. Select the correct option based on the likely intended value.

    Assuming the typo, the angular frequency is 100πRadsec100\pi \frac{\text{Rad}}{\text{sec}}, which corresponds to option 1.

    The final answer is 1. 100πRadsec\boxed{\text{1. } 100\pi \frac{\text{Rad}}{\text{sec}}}.

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