A vinyl record player starts from rest and reaches a final angular velocity of 4pi rad s⁻¹ in 5 seconds. What is its angular acceleration?

The initial angular velocity, since the record starts from rest, is $\omega_i = 0$ rad s$^{-1}$.
The final angular velocity is $\omega_f = 4\pi$ rad s$^{-1}$.
The time taken is $t = 5$ s.

The relationship between initial angular velocity, final angular velocity, angular acceleration ($\alpha$), and time is given by:

The constant angular acceleration is $0.8\pi$ rad s$^{-2}$.

The final answer is $\text{A) } 0.8\pi \text{ rad s}^{-2}$.