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If T = 2π√(L/G), make G the subject of the formula. Hence, find the value of G to the nearest whole number when T = 45, L = 8 and π = 3.142.

Mathematics

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Answers

2 parts
a

G=4π2LT2G = \frac{4\pi^2 L}{T^2}

0
b

N286\text{N286}

Step-by-step solution

10 steps

Part a· 5 steps

To make GG the subject of the formula T=2πLGT = 2\pi \sqrt{\frac{L}{G}}

  1. Divide both sides by 2π2\pi.

    T2π=LG\frac{T}{2\pi} = \sqrt{\frac{L}{G}}
  2. Square both sides of the equation.

    (T2π)2=LG\left(\frac{T}{2\pi}\right)^2 = \frac{L}{G} T24π2=LG\frac{T^2}{4\pi^2} = \frac{L}{G}
  3. Rearrange the equation to solve for GG.

    G=LT24π2G = \frac{L}{\frac{T^2}{4\pi^2}} G=4π2LT2G = \frac{4\pi^2 L}{T^2}

    The formula with GG as the subject is G=4π2LT2\boxed{G = \frac{4\pi^2 L}{T^2}}.

  4. Substitute the given values T=45T=45, L=8L=8, and π=3.142\pi=3.142 into the formula.

    G=4×(3.142)2×8(45)2G = \frac{4 \times (3.142)^2 \times 8}{(45)^2} G=4×9.872164×82025G = \frac{4 \times 9.872164 \times 8}{2025} G=315.9092482025G = \frac{315.909248}{2025} G≈0.15600456G \approx 0.15600456
  5. Round the value of GG to the nearest whole number.

    G≈0G \approx \textbf{0}

    The value of GG to the nearest whole number is 0\boxed{0}.

Part b

N286\text{N286}

Let CC be the cost per person and NN be the number of guests.

The cost per person is partly constant (kk) and partly varies inversely as the number of guests (NN).
This can be written as:

C=k+mNC = k + \frac{m}{N}

where kk and mm are constants.

  1. Use the given information to form two equations.

    For 24 persons, the cost is N800.00:

    800=k+m24(1)800 = k + \frac{m}{24} \quad (1)

    For 18 persons, the cost is N1200.00:

    1200=k+m18(2)1200 = k + \frac{m}{18} \quad (2)
  2. Solve the system of equations for kk and mm.

    Subtract equation (1) from equation (2):

    (1200−800)=(k+m18)−(k+m24)(1200 - 800) = \left(k + \frac{m}{18}\right) - \left(k + \frac{m}{24}\right) 400=m18−m24400 = \frac{m}{18} - \frac{m}{24}

    Find a common denominator for 18 and 24, which is 72.

    400=4m72−3m72400 = \frac{4m}{72} - \frac{3m}{72} 400=m72400 = \frac{m}{72} m=400×72m = 400 \times 72 m=28800m = 28800
  3. Substitute the value of mm into equation (1) to find kk.

    800=k+2880024800 = k + \frac{28800}{24} 800=k+1200800 = k + 1200 k=800−1200k = 800 - 1200 k=−400k = -400

    So the formula for the cost per person is C=−400+28800NC = -400 + \frac{28800}{N}.

  4. Find the cost per person for 42 persons.

    Substitute N=42N = 42 into the formula:

    C=−400+2880042C = -400 + \frac{28800}{42} C=−400+685.71428...C = -400 + 685.71428... C=285.71428...C = 285.71428...
  5. Round the cost to the nearest naira.

    C≈N286C \approx \textbf{N286}

    The cost per person for 42 persons to the nearest naira is N286\boxed{\text{N286}}.

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