Find the area (π = 22/7)

Kutoka kwenye mchoro, kipenyo cha nusu duara ni 14 cm. Hivyo, rediasi ($r$) ni $\frac{14}{2} = 7$ cm.
Tunatumia $\pi = \frac{22}{7}$.

$$\text{Eneo la nusu duara} = \frac{1}{2} \pi r^2$$ $$\text{Eneo la nusu duara} = \frac{1}{2} \times \frac{22}{7} \times (7 \text{ cm})^2$$ $$\text{Eneo la nusu duara} = \frac{1}{2} \times \frac{22}{7} \times 49 \text{ cm}^2$$ $$\text{Eneo la nusu duara} = 11 \times 7 \text{ cm}^2$$ $$\text{Eneo la nusu duara} = 77 \text{ cm}^2$$

Trapeza ina pande mbili sambamba zenye urefu wa 10 cm na 18 cm. Urefu (height) wa trapeza ni 14 cm.

$$\text{Eneo la trapeza} = \frac{1}{2} (a+b) h$$

Ambapo $a = 10 \text{ cm}$, $b = 18 \text{ cm}$, na $h = 14 \text{ cm}$.

$$\text{Eneo la trapeza} = \frac{1}{2} (10 \text{ cm} + 18 \text{ cm}) \times 14 \text{ cm}$$ $$\text{Eneo la trapeza} = \frac{1}{2} (28 \text{ cm}) \times 14 \text{ cm}$$ $$\text{Eneo la trapeza} = 14 \text{ cm} \times 14 \text{ cm}$$ $$\text{Eneo la trapeza} = 196 \text{ cm}^2$$

Eneo la jumla ni jumla ya eneo la nusu duara na eneo la trapeza.

$$\text{Eneo la jumla} = \text{Eneo la nusu duara} + \text{Eneo la trapeza}$$ $$\text{Eneo la jumla} = 77 \text{ cm}^2 + 196 \text{ cm}^2$$ $$\text{Eneo la jumla} = 273 \text{ cm}^2$$

Eneo la jumla la umbo ni $\text{273 cm}^2$.