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If the first term of a geometric series is 4 and the common ratio is 2, find the sum of the first 8 terms.

Mathematics

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Answer

6120511\frac{6120}{511}

Step-by-step solution

4 steps

Hili ni swali kuhusu mfululizo wa kijiometri (geometric series). Tutatumia formula ya jumla ya vigezo vya mfululizo wa kijiometri.

Formula ya jumla ya nn vigezo vya kwanza vya mfululizo wa kijiometri ni:

Sn=a(rn−1)r−1S_n = \frac{a(r^n - 1)}{r - 1}

ambapo aa ni kigezo cha kwanza, rr ni uwiano wa kawaida (common ratio), na nn ni idadi ya vigezo.

  1. Tumia taarifa uliyopewa kupata kigezo cha kwanza (aa).

    Tunajua S9=24S_9 = 24 na r=2r = 2.

    24=a(29−1)2−124 = \frac{a(2^9 - 1)}{2 - 1}
  2. Rahisisha na utatue kwa aa.

    24=a(512−1)124 = \frac{a(512 - 1)}{1} 24=a(511)24 = a(511) a=24511a = \frac{24}{511}
  3. Sasa tumia thamani ya aa uliyopata na r=2r=2 ili kupata jumla ya vigezo 8 vya kwanza (S8S_8).

    S8=a(r8−1)r−1S_8 = \frac{a(r^8 - 1)}{r - 1} S8=24511(28−1)2−1S_8 = \frac{\frac{24}{511}(2^8 - 1)}{2 - 1}
  4. Fanya hesabu.

    S8=24511(256−1)1S_8 = \frac{\frac{24}{511}(256 - 1)}{1} S8=24511(255)S_8 = \frac{24}{511}(255) S8=24×255511S_8 = \frac{24 \times 255}{511} S8=6120511S_8 = \frac{6120}{511}

    Jumla ya vigezo 8 vya kwanza ni:

    6120511\frac{6120}{511}
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