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Verify if the point (2,4) lies on the curve x2 − xy − y2 + 4 = 0.

Mathematics

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Step-by-step solution

2 steps
  1. Verify if the point (2,4)(2,4) lies on the curve x2−xy−y2+4=0x^2 - xy - y^2 + 4 = 0.

    Substitute x=2x=2 and y=4y=4 into the equation:

    22−(2)(4)−42+4=4−8−16+4=−162^2 - (2)(4) - 4^2 + 4 = 4 - 8 - 16 + 4 = -16

    Since −16≠0-16 \neq 0, the point (2,4)(2,4) does not lie on the given curve. For a tangent line to exist at a point, the point must be on the curve.

  2. Make an assumption to proceed.

    We will assume there is a typo in the constant term of the curve's equation, and

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