If (x-5) is a factor of x3 - 4x2 - 11x + 30, find the remaining factors.

$$\begin{array}{c|cccc} 5 & 1 & -4 & -11 & 30 \\ & & 5 & 5 & -30 \\ \hline & 1 & 1 & -6 & 0 \\ \end{array}$$

The coefficients of the quotient are $1, 1, -6$, and the remainder is 0.
This means the quotient is $x^2 + x - 6$.

We need to factor $x^2 + x - 6$. We look for two numbers that multiply to $-6$ and add to 1. These numbers are 3 and $-2$.
So, the quadratic factors as:

$$x^2 + x - 6 = (x+3)(x-2)$$

The remaining factors are $(x+3)$ and $(x-2)$.

Comparing this with the given options:
A. $(x-3)$ and $(x+2)$
B. $(x-3)$ and $(x-2)$
C. $(x+3)$ and $(x-2)$
D. $(x+3)$ and $(x+2)$

The correct option is C.

The final answer is $\boxed{\text{C}}$