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In an examination, a student who scores 25% of the maximum marks fails by 30 marks. Another student who scores 50% of the maximum marks gets 20 marks more than the minimum pass marks. What are the max

Mathematics

ScanSolve AI Answer

Answer

200\text{200}

Step-by-step solution

4 steps
  1. Define variables and set up equations.

    Let MM be the maximum marks for the examination.
    Let PP be the minimum required marks to pass the examination.

    According to the problem, Shubhendu scores 25% of MM and fails by 30 marks. This means his score is P−30P - 30.

    0.25M=P−30(1)0.25M = P - 30 \quad (1)

    Another candidate scores 50% of MM and gets 20 marks more than the minimum required marks. This means his score is P+20P + 20.

    0.50M=P+20(2)0.50M = P + 20 \quad (2)
  2. Express PP in terms of MM from both equations.

    From equation (1):

    P=0.25M+30P = 0.25M + 30

    From equation (2):

    P=0.50M−20P = 0.50M - 20
  3. Equate the expressions for PP and solve for MM.

    Since both expressions equal PP, we can set them equal to each other:

    0.25M+30=0.50M−200.25M + 30 = 0.50M - 20
  4. Isolate MM.

    Subtract 0.25M0.25M from both sides:

    30=0.25M−2030 = 0.25M - 20

    Add 20 to both sides:

    30+20=0.25M30 + 20 = 0.25M 50=0.25M50 = 0.25M

    Divide by 0.25:

    M=500.25M = \frac{50}{0.25} M=50×4M = 50 \times 4 M=200M = 200

    The maximum marks for the examination is 200.

    The final answer is 200\text{200}.

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