In the diagram below, find the value of x.

Mathematics
In the diagram below, find the value of x.

ScanSolve AI Answer

Question 4: Step 1: Analyze the given triangle. The diagram shows a triangle with sides AB = 5 cm, BC = 5 cm, and AC = xx cm. Sides AB and BC have double tick marks, indicating they are equal in length. Side AC has a single tick mark. In basic geometry problems where a specific value for xx is expected without additional information (like angles), different tick marks on all sides often imply that all sides are equal, making it an equilateral triangle. We will proceed with this common interpretation to find a unique value for xx.

Step 2: Determine the value of xx. If the triangle is equilateral, all its sides are equal in length. Therefore, AC=AB=BCAC = AB = BC. x=5 cmx = 5 \text{ cm} The value of xx is 5 cm\boxed{\text{5 cm}}.

Question 5: a) Find the value of xx in the first triangle. Step 1: Identify the angles in the first triangle. The diagram shows a large right-angled triangle. The square symbol indicates a 9090^\circ angle at the bottom left vertex. The angle at the top vertex is split into two parts: 4545^\circ and 3030^\circ. The angle at the bottom right vertex is xx. The total angle at the top vertex is 45+30=7545^\circ + 30^\circ = 75^\circ.

Step 2: Apply the angle sum property of a triangle. The sum of the interior angles in any triangle is 180180^\circ. 90+75+x=18090^\circ + 75^\circ + x = 180^\circ

Step 3: Solve for xx. 165+x=180165^\circ + x = 180^\circ x=180165x = 180^\circ - 165^\circ x=15x = 15^\circ The value of xx is 15\boxed{\text{15}}.

b) Find the value of xx in the second triangle. Step 1: Identify the angles in the second triangle. The diagram shows a right-angled triangle. One angle is xx^\circ, another is 6060^\circ, and the third angle is 9090^\circ (indicated by the square symbol).

Step 2: Apply the angle sum property of a triangle. The sum of the interior angles in any triangle is 180180^\circ. x+60+90=180x^\circ + 60^\circ + 90^\circ = 180^\circ

Step 3: Solve for xx. x+150=180x^\circ + 150^\circ = 180^\circ x=180150x^\circ = 180^\circ - 150^\circ x=30x^\circ = 30^\circ The value of xx is 30\boxed{\text{30}}.

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