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In the following figure, find the value of x.

Mathematics

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Answer

9 cm9 \text{ cm}

Step-by-step solution

4 steps

Haya hapa masuluhisho ya swali ulilotuma:

Qn 18:
Katika mchoro ufuatao, tafuta thamani ya xx.

Mchoro: Mchoro unaonyesha duara yenye kituo O. AB ni tangent kwa duara kwenye B, na urefu wake ni 15 cm. OB ni radius ya duara, na urefu wake ni 8 cm. Mstari AO unapita katikati ya duara, na sehemu ya mstari kutoka A hadi sehemu ya kwanza ya duara (wacha tuiite C) imeandikwa xx.

  1. Tambua pembetatu ya kulia na tumia theorem ya Pythagoras.

    Radius OB ni perpendicular kwa tangent AB kwenye sehemu ya kugusa B. Hivyo, △OBA\triangle OBA ni pembetatu ya kulia na ∠OBA=90∘\angle OBA = 90^\circ.
    Tunajua:

    • OB (radius) = 8 cm8 \text{ cm}
    • AB (tangent) = 15 cm15 \text{ cm} Tunahitaji kupata urefu wa hypotenuse OA.
    OA2=OB2+AB2OA^2 = OB^2 + AB^2 OA2=82+152OA^2 = 8^2 + 15^2 OA2=64+225OA^2 = 64 + 225 OA2=289OA^2 = 289
  2. Kokotoa urefu wa OA.

    OA=289OA = \sqrt{289} OA=17 cmOA = 17 \text{ cm}
  3. Tumia urefu wa OA na radius kupata xx.

    Mstari AO unapita katikati ya duara. Sehemu ya mstari kutoka O hadi kwenye duara (OC) ni radius.
    Hivyo, OC = 8 cm8 \text{ cm}.
    Kutoka kwenye mchoro, tunaona kwamba OA ni jumla ya AC na OC.

    OA=AC+OCOA = AC + OC

    Tunajua OA = 17 cm17 \text{ cm}, AC = xx, na OC = 8 cm8 \text{ cm}.

    17=x+817 = x + 8
  4. Tatua kwa xx.

    x=17−8x = 17 - 8 x=9 cmx = 9 \text{ cm}

    Thamani ya xx ni 9 cm\boxed{9 \text{ cm}}.

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