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In the diagram, DE is parallel to FG. Find the measure of angle DEG in terms of x.

Mathematics

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Answer

x+20∘x+20^\circ

Step-by-step solution

2 steps
  1. Determine the size of ∠DEG\angle DEG in terms of xx.

    Given that DE∥FGDE \parallel FG.
    When two parallel chords are intersected by a transversal chord, the alternate interior angles are equal.
    Consider EG as a transversal intersecting parallel chords DEDE and FGFG.
    Therefore, ∠DEG=∠FGE\angle DEG = \angle FGE (alternate interior angles).
    We are given ∠G1=∠FGE=x+20∘\angle G_1 = \angle FGE = x+20^\circ.
    Thus, ∠DEG=x+20∘\angle DEG = x+20^\circ.

    The size of ∠DEG\angle DEG in terms of xx is x+20∘\boxed{x+20^\circ}.

  2. Calculate the size of $\angle DHG

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