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In the diagram, MK is a tangent to the circle at P, QRP = 50^ and SPK = 62^. Find QPS.

Mathematics

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4. (b) Find the probability that none of them will pass the examination.

  1. Calculate the probability of each person failing the examination.

    P(Mercy fails)=1−P(Mercy passes)=1−23=13P(\text{Mercy fails}) = 1 - P(\text{Mercy passes}) = 1 - \frac{2}{3} = \frac{1}{3}
    P(John fails)=1−P(John passes)=1−58=38P(\text{John fails}) = 1 - P(\text{John passes}) = 1 - \frac{5}{8} = \frac{3}{8}
    P(Alice fails)=1−P(Alice passes)=1−34=14P(\text{Alice fails}) = 1 - P(\text{Alice passes}) = 1 - \frac{3}{4} = \frac{1}{4}

  2. Multiply the probabilities of all three failing, as these are independent events.

    P(none pass)=P(Mercy fails)×P(John fails)×P(Alice fails)P(\text{none pass}) = P(\text{Mercy fails}) \times P(\text{John fails}) \times P(\text{Alice fails}) P(none pass)=13×38×14P(\text{none pass}) = \frac{1}{3} \times \frac{3}{8} \times \frac{1}{4}
  3. Simplify the expression.

    P(none pass)=1×3×13×8×4=396P(\text{none pass}) = \frac{1 \times 3 \times 1}{3 \times 8 \times 4} = \frac{3}{96} P(none pass)=132P(\text{none pass}) = \boxed{\frac{1}{32}}

    4. (c) Find the probability that only Mercy and John will pass the examination.

  4. Identify the probabilities for Mercy passing, John passing, and Alice failing.

    P(Mercy passes)=23P(\text{Mercy passes}) = \frac{2}{3}
    P(John passes)=58P(\text{John passes}) = \frac{5}{8}
    P(Alice fails)=14P(\text{Alice fails}) = \frac{1}{4} (from part b)

  5. Multiply these probabilities together.

    P(only Mercy and John pass)=P(Mercy passes)×P(John passes)×P(Alice fails)P(\text{only Mercy and John pass}) = P(\text{Mercy passes}) \times P(\text{John passes}) \times P(\text{Alice fails}) P(only Mercy and John pass)=23×58×14P(\text{only Mercy and John pass}) = \frac{2}{3} \times \frac{5}{8} \times \frac{1}{4}
  6. Simplify the expression.

    P(only Mercy and John pass)=2×5×13×8×4=1096P(\text{only Mercy and John pass}) = \frac{2 \times 5 \times 1}{3 \times 8 \times 4} = \frac{10}{96} P(only Mercy and John pass)=548P(\text{only Mercy and John pass}) = \boxed{\frac{5}{48}}

    5. (a) In the diagram, MKMK is a tangent to the circle at PP, ∠QRP=50∘\angle QRP = 50^\circ and ∠SPK=62∘\angle SPK = 62^\circ. Find ∠QPS\angle QPS.

  7. Use the Alternate Segment Theorem.

    The angle between a tangent and a chord through the point of contact is equal to the angle in the alternate segment.
    For tangent PKPK and chord PSPS:

    ∠PQS=∠SPK=62∘\angle PQS = \angle SPK = 62^\circ
  8. Use the property that angles subtended by the same arc at the circumference are equal.

    Arc PQPQ subtends ∠PRQ\angle PRQ and ∠PSQ\angle PSQ.

    ∠PSQ=∠PRQ=50∘\angle PSQ = \angle PRQ = 50^\circ
  9. Consider the triangle △PQS\triangle PQS.

    The sum of angles in a triangle is 180∘180^\circ.

    ∠QPS+∠PQS+∠PSQ=180∘\angle QPS + \angle PQS + \angle PSQ = 180^\circ
  10. Substitute the known angles and solve for ∠QPS\angle QPS.

    ∠QPS+62∘+50∘=180∘\angle QPS + 62^\circ + 50^\circ = 180^\circ ∠QPS+112∘=180∘\angle QPS + 112^\circ = 180^\circ ∠QPS=180∘−112∘\angle QPS = 180^\circ - 112^\circ ∠QPS=68∘\angle QPS = \boxed{68^\circ}
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