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Solve the inequality 1 + 1/2 x > 2. If 2/3 of peter's salary is equal to 3/4 of mary's salary - Find peter's salary if Mary's salary is Sh120,000.

Mathematics

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4 parts
1

43\text{}\frac{4}{3}\text{}

2

31∘\text{}31^\circ\text{}

3

x>2\text{}x > 2\text{}

4

Sh135,000\text{}Sh135,000\text{}

Step-by-step solution

17 steps

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Part 1· 6 steps

Tatua kwa xx katika mlinganyo 2x−35+x+12=3x+710\frac{2x-3}{5} + \frac{x+1}{2} = \frac{3x+7}{10}

  1. Tafuta Kigawo Kidogo Zaidi cha Pamoja (LCM) cha madhehebu.

    Madhehebu ni $5, 2,$ na 10. LCM ya $5, 2,$ na 10 ni 10.

  2. Zidisha kila neno kwa LCM.

    Zidisha pande zote mbili za mlinganyo kwa 10 ili kuondoa madhehebu.

    10(2x−35)+10(x+12)=10(3x+710)10 \left(\frac{2x-3}{5}\right) + 10 \left(\frac{x+1}{2}\right) = 10 \left(\frac{3x+7}{10}\right) 2(2x−3)+5(x+1)=1(3x+7)2(2x-3) + 5(x+1) = 1(3x+7)
  3. Panua mabano.

    4x−6+5x+5=3x+74x - 6 + 5x + 5 = 3x + 7
  4. Unganisha vigezo vinavyofanana.

    9x−1=3x+79x - 1 = 3x + 7
  5. Kusanya vigezo vya xx upande mmoja na namba upande mwingine.

    Toa 3x3x kutoka pande zote mbili.

    9x−3x−1=79x - 3x - 1 = 7 6x−1=76x - 1 = 7

    Ongeza 1 pande zote mbili.

    6x=7+16x = 7 + 1 6x=86x = 8
  6. Gawanya kwa 6.

    6x6=86\frac{6x}{6} = \frac{8}{6} x=43x = \frac{4}{3}

    Thamani ya xx ni 43\boxed{\text{}\frac{4}{3}\text{}}

Part 2

31∘\text{}31^\circ\text{}

Tafuta thamani ya XX katika mchoro

  1. Tambua jumla ya pembe kwenye mstari ulionyooka.

    Pembe kwenye mstari ulionyooka hujumlisha hadi 180∘180^\circ. Katika mchoro, tuna pembe tatu: 28∘28^\circ, 90∘90^\circ (iliyowakilishwa na mraba mdogo), na 2X∘2X^\circ.

  2. Andika mlinganyo.

    28∘+90∘+2X∘=180∘28^\circ + 90^\circ + 2X^\circ = 180^\circ
  3. Unganisha namba zinazofanana.

    118∘+2X∘=180∘118^\circ + 2X^\circ = 180^\circ
  4. Tenga 2X∘2X^\circ.

    Toa 118∘118^\circ kutoka pande zote mbili.

    2X∘=180∘−118∘2X^\circ = 180^\circ - 118^\circ 2X∘=62∘2X^\circ = 62^\circ
  5. Tatua kwa XX.

    Gawanya kwa 2.

    X=62∘2X = \frac{62^\circ}{2} X=31∘X = 31^\circ

    Thamani ya XX ni 31∘\boxed{\text{}31^\circ\text{}}

Part 3

x>2\text{}x > 2\text{}

Tatua usawa 1+12x>21 + \frac{1}{2}x > 2

  1. Tenga neno lenye xx.

    Toa 1 kutoka pande zote mbili za usawa.

    12x>2−1\frac{1}{2}x > 2 - 1 12x>1\frac{1}{2}x > 1
  2. Tatua kwa xx.

    Zidisha pande zote mbili kwa 2.

    2(12x)>2(1)2 \left(\frac{1}{2}x\right) > 2(1) x>2x > 2

    Suluhisho la usawa ni x>2\boxed{\text{}x > 2\text{}}

Part 4

Sh135,000\text{}Sh135,000\text{}

Tafuta mshahara wa Peter

  1. Andika taarifa kama mlinganyo.

    Acha mshahara wa Peter uwe PP na mshahara wa Mary uwe MM.
    Tunapewa: "23\frac{2}{3} ya mshahara wa Peter ni sawa na 34\frac{3}{4} ya mshahara wa Mary."
    Hii inaweza kuandikwa kama:

    23P=34M\frac{2}{3}P = \frac{3}{4}M
  2. Badilisha mshahara wa Mary kwenye mlinganyo.

    Tunapewa kuwa mshahara wa Mary ni Sh120,000. Hivyo, M=120,000M = 120,000.

    23P=34(120,000)\frac{2}{3}P = \frac{3}{4}(120,000)
  3. Rahisisha upande wa kulia.

    23P=3×30,000\frac{2}{3}P = 3 \times 30,000 23P=90,000\frac{2}{3}P = 90,000
  4. Tatua kwa PP.

    Ili kupata PP, zidisha pande zote mbili kwa 32\frac{3}{2}.

    P=90,000×32P = 90,000 \times \frac{3}{2} P=45,000×3P = 45,000 \times 3 P=135,000P = 135,000

    Mshahara wa Peter ni Sh135,000\boxed{\text{}Sh135,000\text{}}

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