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Integrate the following functions: 13. integral a^x dx 14. integral (1)/(x2) dx 15. integral x x dx 16. integral (x)/(x+2) dx

Mathematics

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Answer

A

axln⁡a+C\frac{a^x}{\ln a} + C

Step-by-step solution

10 steps

Let's tackle these integration problems.

13. ∫axdx=\int a^x dx =

  1. Apply the standard integration formula for exponential functions.

    The integral of axa^x with respect to xx is axln⁡a+C\frac{a^x}{\ln a} + C, where aa is a constant and a>0,a≠1a > 0, a \neq 1.
    The correct integral is axln⁡a+C\boxed{\frac{a^x}{\ln a} + C}.
    The correct option is (A) axln⁡a+C\frac{a^x}{\ln a} + C.

    14. ∫1x2dx=\int \frac{1}{x^2} dx =

  2. Rewrite the integrand using negative exponents.

    ∫x−2dx\int x^{-2} dx
  3. Apply the power rule for integration, ∫xndx=xn+1n+1+C\int x^n dx = \frac{x^{n+1}}{n+1} + C.

    x−2+1−2+1+C=x−1−1+C\frac{x^{-2+1}}{-2+1} + C = \frac{x^{-1}}{-1} + C
  4. Simplify the expression.

    −1x+C-\frac{1}{x} + C

    The correct integral is −1x+C\boxed{-\frac{1}{x} + C}.

    15. ∫sec⁡xtan⁡x dx=\int \sec x \tan x \, dx =

  5. Recall the derivative of trigonometric functions.

    The derivative of sec⁡x\sec x is sec⁡xtan⁡x\sec x \tan x.

  6. Therefore, the integral of sec⁡xtan⁡x\sec x \tan x is sec⁡x\sec x.

    ∫sec⁡xtan⁡x dx=sec⁡x+C\int \sec x \tan x \, dx = \sec x + C

    The correct integral is sec⁡x+C\boxed{\sec x + C}.

    16. ∫xx+2dx=\int \frac{x}{x+2} dx =

  7. Rewrite the numerator to simplify the fraction.

    Add and subtract 2 in the numerator.

    ∫x+2−2x+2dx\int \frac{x+2-2}{x+2} dx
  8. Split the fraction into two terms.

    ∫(x+2x+2−2x+2)dx\int \left( \frac{x+2}{x+2} - \frac{2}{x+2} \right) dx
  9. Simplify the first term and separate the integrals.

    ∫(1−2x+2)dx=∫1 dx−∫2x+2dx\int \left( 1 - \frac{2}{x+2} \right) dx = \int 1 \, dx - \int \frac{2}{x+2} dx
  10. Integrate each term.

    x−2ln⁡∣x+2∣+Cx - 2 \ln|x+2| + C

    The correct integral is x−2ln⁡∣x+2∣+C\boxed{x - 2 \ln|x+2| + C}.

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