John has swimming lessons every fifth day and diving lessons every third day. If he had a swimming lesson and a diving lesson on 17 October 2019, when will be the next date on which he has both swimming and diving lessons?

Mathematics
John has swimming lessons every fifth day and diving lessons every third day. If he had a swimming lesson and a diving lesson on 17 October 2019, when will be the next date on which he has both swimming and diving lessons?

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Answer

15thday15^{th} day

Question 1

Step 1: John has swimming lessons every 5 days and diving lessons every 3 days. Both lessons occur together every LCM(5, 3) days.

LCM(5,3)=5×3gcd(5,3)=151=15LCM(5, 3) = \frac{5 \times 3}{\gcd(5, 3)} = \frac{15}{1} = 15

He will have both lessons on the 15th15^{th} day.

15^{th day}

Question 2

Step 1: The greatest number of parties, where each uses the same number of white and orange balloons, is the GCD of 24 and 16.

Euclidean algorithm:

24=1×16+824 = 1 \times 16 + 8 16=2×8+016 = 2 \times 8 + 0

GCD(24,16)=8(24, 16) = 8.

Step 2: Number of white balloons per party: 24÷8=324 \div 8 = 3.

Number of orange balloons per party: 16÷8=216 \div 8 = 2.

The greatest number of parties is 8.

8

Question 3: Write numbers in standard form (scientific notation) correct to 3 significant figures.

3(i) 2.87457602.8745760

Step 1: Identify first 3 significant figures: 2, 8, 7. Fourth digit is 4 (<5, no rounding).

2.87×100orsimply2.872.87 \times 10^{0} \quad or simply \quad 2.87

2.87

3(ii) 2.38575×1062.38575 \times 10^{6}

Step 1: Mantissa 2.385752.38575, first 3 significant figures: 2, 3, 8. Fourth digit 5 followed by 7 (>0), round up 8 to 9.

2.39×1062.39 \times 10^{6}

2.39 \times 10^{6}

3(iii) 0.00002385×1060.00002385 \times 10^{-6}

Step 1: Simplify the number.

0.00002385=2.385×1050.00002385 = 2.385 \times 10^{-5} 2.385×105×106=2.385×10112.385 \times 10^{-5} \times 10^{-6} = 2.385 \times 10^{-11}

Step 2: Round mantissa 2.3852.385 to 3 significant figures. First 3: 2, 3, 8. Fourth digit 5, round up 8 to 9 (common convention for homework).

2.39×10112.39 \times 10^{-11}

2.39 \times 10^{-11}

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Quick Answer

Question 1 Step 1: John has swimming lessons every 5 days and diving lessons every 3 days.

John has swimming lessons every fifth day and diving lessons every third day. If he had a swimming lesson and a diving lesson on 17 October 2019, when will be the next date on which he has both swimming and diving lessons?
Mathematics

This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

ScanSolve AI Answer
Question 1 Step 1: John has swimming lessons every 5 days and diving lessons every 3 days. Both lessons occur together every LCM(5, 3) days. LCM(5, 3) = (5 × 3)/((5, 3)) = (15)/(1) = 15 He will have both lessons on the 15^th day. 15^th day Question 2 Step 1: The greatest number of parties, where each uses the same number of white and orange balloons, is the GCD of 24 and 16. Euclidean algorithm: 24 = 1 × 16 + 8 16 = 2 × 8 + 0 GCD(24, 16) = 8. Step 2: Number of white balloons per party: 24 ÷ 8 = 3. Number of orange balloons per party: 16 ÷ 8 = 2. The greatest number of parties is 8. 8 Question 3: Write numbers in standard form (scientific notation) correct to 3 significant figures. 3(i) 2.8745760 Step 1: Identify first 3 significant figures: 2, 8, 7. Fourth digit is 4 (<5, no rounding). 2.87 × 10^0 or simply 2.87 2.87 3(ii) 2.38575 × 10^6 Step 1: Mantissa 2.38575, first 3 significant figures: 2, 3, 8. Fourth digit 5 followed by 7 (>0), round up 8 to 9. 2.39 × 10^6 2.39 × 10^6 3(iii) 0.00002385 × 10^-6 Step 1: Simplify the number. 0.00002385 = 2.385 × 10^-5 2.385 × 10^-5 × 10^-6 = 2.385 × 10^-11 Step 2: Round mantissa 2.385 to 3 significant figures. First 3: 2, 3, 8. Fourth digit 5, round up 8 to 9 (common convention for homework). 2.39 × 10^-11 2.39 × 10^-11