John starts at O. He travels 40 km on a bearing of 210 degrees to reach town T. Find the coordinates of town T.

April 19, 2026Mathematics

ScanSolve AI Answer

April 19, 2026

Answer

90^\circ - \text{bearing}$.

a) Step 1: Determine the coordinates of town T from John's initial position. Let John's initial position be the origin $O(0,0)$ . John travels 40 km on a bearing of $210^\circ$ . To convert a bearing to a standard angle $\theta$ (measured counter-clockwise from the positive x-axis), we use $\theta = 90^\circ - \text{bearing}$ . For a bearing of $210^\circ$ : $\theta_T = 90^\circ - 210^\circ = -120^\circ$ . The coordinates of T are $(x_T, y_T)$ :

Was this helpful?

Need help with your own homework?

Get instant step-by-step solutions to any question. Free to start.

Ask Your Question

More Mathematics Questions

QA hard disk of 4gb is required to store a pile of 800mb and another pile of 2.4gb. What capacity of…QAssignment 1 1002 ÷ 112 2 728 × 168 3 10102 × 112 4 6248 + 2428 5 Convert 2408 to binary QAssignment: 1) 1001/2 ÷ 11/2, 2) 728 x 168, 3) 10101/2 x 11/2, 4) 6248 + 2428, 5) Convert 240 to bin…Qउपयुक्त सर्वसमिका के उपयोग से, निम्नलिखित के मान ज्ञात कीजिए। (i) x3 - 8y3 - 6x2y + 12xy2 (ii) 27a3…QCalculate the perimeter of the square with side length 30.

See all Mathematics questions →

Still have questions?

Quick Answer

a) Step 1: Determine the coordinates of town T from John's initial position. Let John's initial position be the origin O(0,0).

Asked on April 19, 2026Mathematics

This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

ScanSolve AI AnswerAnswered on April 19, 2026

a) Step 1: Determine the coordinates of town T from John's initial position. Let John's initial position be the origin O(0,0). John travels 40 km on a bearing of 210^. To convert a bearing to a standard angle (measured counter-clockwise from the positive x-axis), we use = 90^ - bearing. For a bearing of 210^: _T = 90^ - 210^ = -120^. The coordinates of T are (x_T, y_T): x_T = 40 (-1