Julian's church hosted a bazaar to raise funds. The ticket cost R100, a minimum amount just to enter the hall but once you are inside all items cost R10. The graph below shows the total cost in rand (C), after having n items to buy.

First, let's complete the table using the information provided. The problem states that the ticket cost is R100 to enter, and each item costs R10. The graph also shows that at 0 items, the cost is R100. This means the total cost (C) is R100 plus R10 for each item (n). So, the formula is $C = 100 + 10n$.

The table provided has an entry for $n=1$ with $C=100$. This contradicts the problem description and the graph, which show that for $n=1$, the cost should be $100 + 10(1) = 110$. We will proceed with the formula $C = 100 + 10n$ derived from the problem statement and the graph.

Here is the completed table:

No. of items (n)	1	3	5	6	7
Cost in rand (C)	110	130	150	160	170

Now, let's answer the questions: