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Find the latitude soup of me equator sum that when one travels along the latitude for 80 nm, a change of 2° in longitude is made.

Mathematics

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5) Tafuta umbali katika nautical miles kati ya pointi A(45∘N,35∘W45^\circ N, 35^\circ W) na B(45∘N,100∘E45^\circ N, 100^\circ E) kando ya sambamba ya latitudo.

Kazi yako ni sahihi kabisa.
Tofauti ya longitudo ni 35∘+100∘=135∘35^\circ + 100^\circ = 135^\circ.
Umbali katika km:

Dkm=135∘360∘×2π(6370 km)cos⁡(45∘)≈10609.95 kmD_{km} = \frac{135^\circ}{360^\circ} \times 2\pi (6370 \text{ km}) \cos(45^\circ) \approx 10609.95 \text{ km}

Umbali katika nm:

Dnm=10609.95 km1.852 km/nm≈5728.97 nmD_{nm} = \frac{10609.95 \text{ km}}{1.852 \text{ km/nm}} \approx 5728.97 \text{ nm}

Kukamilisha kwa namba nzima:

5729 nm\boxed{\text{5729 nm}}

✅ Correct. Mahesabu yako yanalandana na jibu sahihi.

6) Tafuta latitudo kusini mwa ikweta ambapo unaposafiri kando ya latitudo kwa 80 nm, mabadiliko ya 2∘2^\circ katika longitudo hufanywa.

Umeandika fomula sahihi:

D=θ360∘×2πRcos⁡αD = \frac{\theta}{360^\circ} \times 2\pi R \cos \alpha

Kutoka hapa, unahitaji kupanga upya fomula ili kupata cos⁡α\cos \alpha na kisha α\alpha.
Umbali D=80 nm=148.16 kmD = 80 \text{ nm} = 148.16 \text{ km}. Tofauti ya longitudo θ=2∘\theta = 2^\circ.

cos⁡α=D×360∘2πRθ\cos \alpha = \frac{D \times 360^\circ}{2\pi R \theta} cos⁡α=148.16 km×360∘2π(6370 km)×2∘≈0.66631\cos \alpha = \frac{148.16 \text{ km} \times 360^\circ}{2\pi (6370 \text{ km}) \times 2^\circ} \approx 0.66631 α=cos⁡−1(0.66631)≈48.21∘\alpha = \cos^{-1}(0.66631) \approx 48.21^\circ

Kwa kuwa inatafutwa latitudo kusini mwa ikweta:

48.21∘S\boxed{48.21^\circ S}

✅ Correct. Fomula yako ni sahihi na jibu la mwisho ni 48.21∘S48.21^\circ S.

7) Tafuta umbali kati ya pointi P(35∘N,50∘E35^\circ N, 50^\circ E) na Q(26∘30′S,50∘E26^\circ 30' S, 50^\circ E) kwenye uso wa Dunia.

Kazi yako ni sahihi. Pointi ziko kwenye longitudo moja, kwa hivyo tunatumia fomula ya duara kuu.
Tofauti ya latitudo ni 35∘+26∘30′=61.5∘35^\circ + 26^\circ 30' = 61.5^\circ.
Umbali katika km:

Dkm=61.5∘360∘×2π(6370 km)≈6824.96 kmD_{km} = \frac{61.5^\circ}{360^\circ} \times 2\pi (6370 \text{ km}) \approx 6824.96 \text{ km}

Kukamilisha kwa namba nzima:

6825 km\boxed{\text{6825 km}}

Umbali katika nm:

Dnm=6824.96 km1.852 km/nm≈3685.18 nmD_{nm} = \frac{6824.96 \text{ km}}{1.852 \text{ km/nm}} \approx 3685.18 \text{ nm}

Kukamilisha kwa namba nzima:

3685 nm\boxed{\text{3685 nm}}

✅ Correct. Mahesabu yako yanalandana na majibu sahihi.

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