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Find the Least Common Multiple (LCM) of the given algebraic expressions and numbers.

Mathematics

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Step-by-step solution

12 steps

Here are the solutions to the problems.

4)

  1. Factorize each expression.

    x2+x=x(x+1)x^2 + x = x(x+1) x2−1=(x−1)(x+1)x^2 - 1 = (x-1)(x+1) x2−x=x(x−1)x^2 - x = x(x-1)
  2. Identify all unique factors and their highest powers.

    The unique factors are xx, (x+1)(x+1), and (x−1)(x-1). Each appears with a highest power of 1.

  3. Multiply these highest powers together to find the L.C.M.

    L.C.M=x(x+1)(x−1)\text{L.C.M} = x(x+1)(x-1)

    This can also be written as:

    L.C.M=x(x2−1)=x3−x\text{L.C.M} = x(x^2-1) = x^3-x x(x2−1) or x3−x\boxed{x(x^2-1) \text{ or } x^3-x}

    5)

  4. Find the prime factorization of each number.

    9=329 = 3^2 15=3×515 = 3 \times 5 20=22×520 = 2^2 \times 5 24=23×324 = 2^3 \times 3
  5. Identify all unique prime factors and their highest powers.

    • Highest power of 2: 232^3
    • Highest power of 3: 323^2
    • Highest power of 5: 515^1
  6. Multiply these highest powers together to find the L.C.M.

    L.C.M=23×32×51=8×9×5=72×5=360\text{L.C.M} = 2^3 \times 3^2 \times 5^1 = 8 \times 9 \times 5 = 72 \times 5 = 360

    The least number of sweets is 360.

    360\boxed{360}

    6)

  7. Find the prime factorization of each number.

    27=3327 = 3^3 30=2×3×530 = 2 \times 3 \times 5 45=32×545 = 3^2 \times 5
  8. Identify all unique prime factors and their highest powers.

    • Highest power of 2: 212^1
    • Highest power of 3: 333^3
    • Highest power of 5: 515^1
  9. Multiply these highest powers together to find the L.C.M.

    L.C.M=21×33×51=2×27×5=54×5=270\text{L.C.M} = 2^1 \times 3^3 \times 5^1 = 2 \times 27 \times 5 = 54 \times 5 = 270
  10. Add the remainder to the L.C.M.

    to find nn.
    Since the remainder is always 3, n=L.C.M+3n = \text{L.C.M} + 3.

    n=270+3=273n = 270 + 3 = 273 273\boxed{273}

    7)

  11. Find the prime factorization of each number (20, 24, 28).

    20=22×520 = 2^2 \times 5 24=23×324 = 2^3 \times 3 28=22×728 = 2^2 \times 7
  12. Identify all unique prime factors and their highest powers.

    • Highest power of 2: 232^3
    • Highest power of 3: 313^1
    • Highest power of 5:
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