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Let f(x) be a function such that f(2) = 18. Find the limit of (f(x) - 18 - (x-2)2)/(f(x) - 18 - 2(x-2)2) as x approaches 2.

Mathematics

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To find the limit, we first evaluate the numerator and denominator at x=2x=2.
Let N(x)=f(x)−18−(x−2)2N(x) = f(x) - 18 - (x-2)^2 and D(x)=f(x)−18−2(x−2)2D(x) = f(x) - 18 - 2(x-2)^2.

Step 1: Evaluate N(2)N(2) and D(2)D(2).
Given f(2)=18f(2)=18.

N(2)=f(2)−18−(2−2)2=18−18−02=0N(2) = f(2) - 18 - (2-2)^2 = 18 - 18 - 0^2 = 0
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