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Let x y = x + y + 10. Find (a) the identity element and (b) the inverses of 3 and -5.

Mathematics

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1. (a) Identity element

  1. Define the identity element ee.

    For a binary operation xΔy=x+y+10x \Delta y = x + y + 10, the identity element ee is such that xΔe=xx \Delta e = x for all x∈Rx \in R.

  2. Solve for ee.

    x+e+10=xx + e + 10 = x e+10=0e + 10 = 0 e=−10e = -10

    The identity element is −10\boxed{-10}.

    1. (b) Inverses of 3 and -5

  3. Define the inverse element.

    The inverse of an element aa, denoted a−1a^{-1}, is such that aΔa−1=ea \Delta a^{-1} = e. We found e=−10e = -10.

  4. Find the inverse of 3.

    Let the inverse of 3 be aa.

    3Δa=e3 \Delta a = e 3+a+10=−103 + a + 10 = -10 a+13=−10a + 13 = -10 a=−10−13a = -10 - 13 a=−23a = -23

    The inverse of 3 is −23\boxed{-23}.

  5. Find the inverse of -5.

    Let the inverse of -5 be bb.

    −5Δb=e-5 \Delta b = e −5+b+10=−10-5 + b + 10 = -10 b+5=−10b + 5 = -10 b=−10−5b = -10 - 5 b=−15b = -15

    The inverse of -5 is −15\boxed{-15}.

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