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Find the lim_x→2 (x2-4)/(x-2)

Mathematics

ScanSolve AI Answer

Answer

4\textbf{4}

Step-by-step solution

5 steps
  1. Identify the limit expression.

    The given limit is:

    lim⁡x→2x2−4x−2\lim_{x \to 2} \frac{x^2 - 4}{x - 2}
  2. Check for indeterminate form.

    If we substitute x=2x=2 directly into the expression, we get 22−42−2=4−40=00\frac{2^2 - 4}{2 - 2} = \frac{4 - 4}{0} = \frac{0}{0}, which is an indeterminate form. This means we need to simplify the expression.

  3. Factor the numerator.

    The numerator x2−4x^2 - 4 is a difference of squares, which can be factored as (x−2)(x+2)(x - 2)(x + 2).

    x2−4=(x−2)(x+2)x^2 - 4 = (x - 2)(x + 2)
  4. Simplify the expression.

    Substitute the factored numerator back into the limit expression:

    lim⁡x→2(x−2)(x+2)x−2\lim_{x \to 2} \frac{(x - 2)(x + 2)}{x - 2}

    Since x→2x \to 2, xx is approaching 2 but is not equal to 2. Therefore, x−2≠0x - 2 \neq 0, and we can cancel out the (x−2)(x - 2) term from the numerator and denominator.

    lim⁡x→2(x+2)\lim_{x \to 2} (x + 2)
  5. Evaluate the limit.

    Now, substitute x=2x=2 into the simplified expression:

    2+2=42 + 2 = 4

    The limit is 4\textbf{4}.

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