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Find the limit of the following functions as x approaches c: i) f(x) = x2, ii) f(x) = 1/x, iii) f(x) = sqrt(x)

Mathematics

ScanSolve AI Answer

Answer

i

2c

Step-by-step solution

15 steps

Here are the limits for each function:

Part i· 4 steps

For f(x)=x2f(x) = x^2

  1. Substitute f(x)f(x) and f(c)f(c) into the limit expression.

    lim⁡x→cx2−c2x−c\lim_{x \to c} \frac{x^2 - c^2}{x-c}
  2. Factor the numerator using the difference of squares formula, a2−b2=(a−b)(a+b)a^2 - b^2 = (a-b)(a+b).

    lim⁡x→c(x−c)(x+c)x−c\lim_{x \to c} \frac{(x-c)(x+c)}{x-c}
  3. Cancel out the (x−c)(x-c) term, since x≠cx \neq c as x→cx \to c.

    lim⁡x→c(x+c)\lim_{x \to c} (x+c)
  4. Substitute x=cx=c into the simplified expression.

    c+c=2cc+c = 2c

    The limit is 2c\boxed{2c}.

Part ii· 6 steps

For f(x)=1xf(x) = \frac{1}{x}

  1. Substitute f(x)f(x) and f(c)f(c) into the limit expression.

    lim⁡x→c1x−1cx−c\lim_{x \to c} \frac{\frac{1}{x} - \frac{1}{c}}{x-c}
  2. Combine the fractions in the numerator.

    lim⁡x→cc−xxcx−c\lim_{x \to c} \frac{\frac{c-x}{xc}}{x-c}
  3. Rewrite the expression by multiplying the numerator by the reciprocal of the denominator.

    lim⁡x→cc−xxc(x−c)\lim_{x \to c} \frac{c-x}{xc(x-c)}
  4. Factor out −1-1 from the numerator to match the term in the denominator.

    lim⁡x→c−(x−c)xc(x−c)\lim_{x \to c} \frac{-(x-c)}{xc(x-c)}
  5. Cancel out the (x−c)(x-c) term.

    lim⁡x→c−1xc\lim_{x \to c} \frac{-1}{xc}
  6. Substitute x=cx=c into the simplified expression.

    −1c⋅c=−1c2\frac{-1}{c \cdot c} = \frac{-1}{c^2}

    The limit is ∗−1c2∗\boxed*{-\frac{1}{c^2}}*.

Part iii· 5 steps

For f(x)=xf(x) = \sqrt{x}

  1. Substitute f(x)f(x) and f(c)f(c) into the limit expression.

    lim⁡x→cx−cx−c\lim_{x \to c} \frac{\sqrt{x} - \sqrt{c}}{x-c}
  2. Multiply the numerator and denominator by the conjugate of the numerator, x+c\sqrt{x}+\sqrt{c}.

    lim⁡x→cx−cx−c⋅x+cx+c\lim_{x \to c} \frac{\sqrt{x} - \sqrt{c}}{x-c} \cdot \frac{\sqrt{x}+\sqrt{c}}{\sqrt{x}+\sqrt{c}}
  3. Apply the difference of squares formula (a−b)(a+b)=a2−b2(a-b)(a+b) = a^2 - b^2 to the numerator.

    lim⁡x→c(x)2−(c)2(x−c)(x+c)\lim_{x \to c} \frac{(\sqrt{x})^2 - (\sqrt{c})^2}{(x-c)(\sqrt{x}+\sqrt{c})} lim⁡x→cx−c(x−c)(x+c)\lim_{x \to c} \frac{x-c}{(x-c)(\sqrt{x}+\sqrt{c})}
  4. Cancel out the (x−c)(x-c) term.

    lim⁡x→c1x+c\lim_{x \to c} \frac{1}{\sqrt{x}+\sqrt{c}}
  5. Substitute x=cx=c into the simplified expression.

    1c+c=12c\frac{1}{\sqrt{c}+\sqrt{c}} = \frac{1}{2\sqrt{c}}

    The limit is ∗12c∗\boxed*{\frac{1}{2\sqrt{c}}}*.

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