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Solve the logarithmic equation: 2 _x (33/8) = 6

Mathematics

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Answer

\text{3^{1/8}}

Step-by-step solution

6 steps

Let's solve this logarithmic equation.

  1. Write down the given equation.

    2log⁡x(33/8)=62 \log_x (3^{3/8}) = 6
  2. Divide both sides by 2 to isolate the logarithm.

    log⁡x(33/8)=62\log_x (3^{3/8}) = \frac{6}{2} log⁡x(33/8)=3\log_x (3^{3/8}) = 3
  3. Apply the power rule of logarithms, which states that log⁡b(Mp)=plog⁡b(M)\log_b (M^p) = p \log_b (M).

    38log⁡x(3)=3\frac{3}{8} \log_x (3) = 3
  4. Multiply both sides by 83\frac{8}{3} to isolate log⁡x(3)\log_x (3).

    log⁡x(3)=3×83\log_x (3) = 3 \times \frac{8}{3} log⁡x(3)=8\log_x (3) = 8
  5. Convert the logarithmic equation to its exponential form.

    If log⁡bA=C\log_b A = C, then bC=Ab^C = A.

    x8=3x^8 = 3
  6. Solve for xx by taking the eighth root of both sides.

    x=31/8x = 3^{1/8}

    The value of xx is \boxed{\text{3^{1/8}}}.

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