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M varies jointly as N and inversely as the square root of R. If M = 35 when N = 7 and R = 9, find the equation connecting M, N and R. Find R when M = 42 and N = 15. Find the percentage change in M whe

Mathematics

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Answers

3 parts
i

M=15NRM = \frac{15N}{\sqrt{R}}

ii

5625196\frac{5625}{196}

iii

56.25%56.25\%

Step-by-step solution

11 steps

Here are the solutions to the problem:

Part i· 4 steps

Find the equation connecting M, N and R.

  1. Write the proportionality relationship.

    M varies jointly as N, so M∝NM \propto N.
    M varies inversely as the square root of R, so M∝1RM \propto \frac{1}{\sqrt{R}}.
    Combining these, we get:

    M∝NRM \propto \frac{N}{\sqrt{R}}
  2. Introduce the constant of proportionality, kk.

    M=kNRM = \frac{kN}{\sqrt{R}}
  3. Use the given values (M=35M=35, N=7N=7, R=9R=9) to find kk.

    35=k⋅7935 = \frac{k \cdot 7}{\sqrt{9}} 35=7k335 = \frac{7k}{3}

    Multiply both sides by 3:

    35×3=7k35 \times 3 = 7k 105=7k105 = 7k

    Divide by 7:

    k=1057k = \frac{105}{7} k=15k = 15
  4. Substitute the value of kk back into the equation.

    M=15NRM = \frac{15N}{\sqrt{R}}

    The equation connecting M, N, and R is M=15NR\boxed{M = \frac{15N}{\sqrt{R}}}.

Part ii

5625196\frac{5625}{196}

Find R when M = 42 and N = 15.

  1. Use the equation from Part (i).

    M=15NRM = \frac{15N}{\sqrt{R}}
  2. Substitute the given values (M=42M=42, N=15N=15).

    42=15⋅15R42 = \frac{15 \cdot 15}{\sqrt{R}} 42=225R42 = \frac{225}{\sqrt{R}}
  3. Solve for R\sqrt{R}.

    R=22542\sqrt{R} = \frac{225}{42}

    Simplify the fraction:

    R=7514\sqrt{R} = \frac{75}{14}
  4. Square both sides to find R.

    R=(7514)2R = \left(\frac{75}{14}\right)^2 R=752142R = \frac{75^2}{14^2} R=5625196R = \frac{5625}{196}

    The value of R is 5625196\boxed{\frac{5625}{196}}.

Part iii

56.25%56.25\%

Find the percentage change in M when N is increased by 25% and R reduced by 36%.

  1. Express the new values of N and R in terms of their original values.

    Let the original values be N1N_1 and R1R_1. The original M is M1=15N1R1M_1 = \frac{15N_1}{\sqrt{R_1}}.
    N is increased by 25%, so the new N, N2N_2, is:

    N2=N1+0.25N1=1.25N1N_2 = N_1 + 0.25N_1 = 1.25N_1

    R is reduced by 36%, so the new R, R2R_2, is:

    R2=R1−0.36R1=0.64R1R_2 = R_1 - 0.36R_1 = 0.64R_1
  2. Calculate the new value of M, M2M_2.

    M2=15N2R2M_2 = \frac{15N_2}{\sqrt{R_2}}

    Substitute N2=1.25N1N_2 = 1.25N_1 and R2=0.64R1R_2 = 0.64R_1:

    M2=15(1.25N1)0.64R1M_2 = \frac{15(1.25N_1)}{\sqrt{0.64R_1}} M2=15(1.25N1)0.8R1M_2 = \frac{15(1.25N_1)}{0.8\sqrt{R_1}}

    Rearrange the terms to relate M2M_2 to M1M_1:

    M2=1.250.8⋅(15N1R1)M_2 = \frac{1.25}{0.8} \cdot \left(\frac{15N_1}{\sqrt{R_1}}\right)

    Since M1=15N1R1M_1 = \frac{15N_1}{\sqrt{R_1}}:

    M2=1.250.8M1M_2 = \frac{1.25}{0.8} M_1

    Calculate the fraction:

    1.250.8=12580=2516=1.5625\frac{1.25}{0.8} = \frac{125}{80} = \frac{25}{16} = 1.5625

    So, M2=1.5625M1M_2 = 1.5625 M_1.

  3. Calculate the percentage change in M.

    Percentage change =M2−M1M1×100%= \frac{M_2 - M_1}{M_1} \times 100\%
    Percentage change =1.5625M1−M1M1×100%= \frac{1.5625 M_1 - M_1}{M_1} \times 100\%
    Percentage change =(1.5625−1)×100%= (1.5625 - 1) \times 100\%
    Percentage change =0.5625×100%= 0.5625 \times 100\%
    Percentage change =56.25%= 56.25\%
    The percentage change in M is an increase of 56.25%\boxed{56.25\%}.

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