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How many different signals can be made using 4 flags from a set of 7 different flags, if the order of the flags matters?

Mathematics

ScanSolve AI Answer

Answer

840

Step-by-step solution

5 steps

Here's how to solve the problem:

  1. Identify the type of problem.

    This is a permutation problem because the order of the flags matters for a signal (e.g., red-blue-green-yellow is different from blue-red-green-yellow). We are selecting a specific number of items from a larger set and arranging them.

  2. Determine the total number of items (nn) and the number of items to be arranged (rr).

    We have 7 flags of different colors, so n=7n = 7.
    We are using exactly 4 flags for each signal, so r=4r = 4.

  3. Apply the permutation formula.

    The number of permutations of nn items taken rr at a time is given by the formula:

    P(n,r)=n!(n−r)!P(n, r) = \frac{n!}{(n-r)!}

    Substitute the values of nn and rr:

    P(7,4)=7!(7−4)!P(7, 4) = \frac{7!}{(7-4)!} P(7,4)=7!3!P(7, 4) = \frac{7!}{3!}
  4. Calculate the factorials and simplify.

    P(7,4)=7×6×5×4×3×2×13×2×1P(7, 4) = \frac{7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1}{3 \times 2 \times 1}

    Cancel out 3×2×13 \times 2 \times 1 from the numerator and denominator:

    P(7,4)=7×6×5×4P(7, 4) = 7 \times 6 \times 5 \times 4
  5. Perform the multiplication.

    P(7,4)=42×20P(7, 4) = 42 \times 20 P(7,4)=840P(7, 4) = 840

    There are 840\boxed{840} different signals that can be made.

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