How many distinct four-digit numbers can be formed using the digits 1, 2, 3, and 4 without repetition?

Here are the solutions to the exercises: 7) To find the number of ways the digits 1, 2, 3, and 4 can be arranged to form a four-digit number, we calculate the permutations of 4 distinct items. Step 1: Identify the number of distinct digits. There are 4 distinct digits: 1, 2, 3, 4. Step 2: Calculate the factorial of the number of digits. Number of ways = 4! = 4 × 3 × 2 × 1 = 24 The given answer is 24 ways. The answer is 24 ways. 8) To find

How many distinct four-digit numbers can be formed using the digits 1, 2, 3, and 4 without repetition?

Here are the solutions to the exercises: 7) To find the number of ways the digits 1, 2, 3, and 4 can be arranged to form a four-digit number, we calculate the permutations of 4 distinct items. Step 1: Identify the number of distinct digits. There are 4 distinct digits: 1, 2, 3, 4. Step 2: Calculate the factorial of the number of digits. Number of ways = 4! = 4 × 3 × 2 × 1 = 24 The given answer is 24 ways. The answer is 24 ways. 8) To find

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Here are the solutions to the exercises:

7) To find the number of ways the digits 1, 2, 3, and 4 can be arranged to form a four-digit number, we calculate the permutations of 4 distinct items.

Identify the number of distinct digits.
There are 4 distinct digits: 1, 2, 3, 4.
Calculate the factorial of the number of digits.
$\text{Number of ways} = 4! = 4 \times 3 \times 2 \times 1 = 24$
The given answer is 24 ways.
The answer is $\boxed{\text{24 ways}}$ .

8) To find

How many distinct four-digit numbers can be formed using the digits 1, 2, 3, and 4 without repetition?

Step-by-step solution

Identify the number of distinct digits.

Calculate the factorial of the number of digits.

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